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baherus [9]
3 years ago
11

A friend lends you the eyepiece of his microscope to use on your own microscope. He claims that since his eyepiece has the same

diameter as yours but twice the focal length, the resolving power of your microscope will be doubled. Is his claim valid? Explain.
Physics
1 answer:
asambeis [7]3 years ago
8 0

Answer:

The resolving power remains same.

Explanation:

The resolving power of the lens is directly proportional to the diameter of the lens not on the focal length.

As the diameter is same but the focal length is doubled so the resolving power remains same.

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Two small identical conducting spheres are placed with their centers 0.41 m apart. One is given a charge of 12 ✕ 10−9 C, the oth
nataly862011 [7]

(a) -1.48\cdot 10^{-5}N

The electrostatic force exerted between the two sphere is given by:

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1, q2 are the charges on the two spheres

r is the separation between the centres of the two spheres

In this problem,

q_1 = 12\cdot 10^{-9} C\\q_2 = -23\cdot 10^{-9} C\\r = 0.41 m

Substituting these values into the equation, we find the force

F=(9\cdot 10^9 Nm^2 C^{-2} )\frac{(12\cdot 10^{-9}C)(-23\cdot 10^{-9} C)}{(0.41 m)^2}=-1.48\cdot 10^{-5}N

And the negative sign means the force is attractive, since the two spheres have charges of opposite sign.

(b) +1.62\cdot 10^{-6}N

The total net charge over the two sphere is:

Q=q_1 +q_2 = 12\cdot 10^{-9}C+(-23\cdot 10^{-9}C)=-11\cdot 10^{-9} C

When the two spheres are connected, the charge distribute equally over the two spheres (since they are identical, they have same capacitance), so each sphere will have a charge of

q=\frac{Q}{2}=\frac{-11\cdot 10^{-9}C}{2}=-5.5\cdot 10^{-9}C

So the electrostatic force between the two spheres will now be

F=k\frac{q^2}{r^2}

And substituting numbers, we find

F=(9\cdot 10^9 Nm^2 C^{-2} )\frac{(-5.5\cdot 10^{-9} C)^2}{(0.41 m)^2}=+1.62\cdot 10^{-6}N

and the positive sign means the force is repulsive, since the two spheres have same sign charges.

7 0
3 years ago
Water that soaks into Earth may become _____ under the surface.
larisa [96]
If it soaks into the earths surface it becomes ground water

5 0
3 years ago
Which scientist discovered the two radioactive elements radium and polonium?
kolezko [41]
The scientist who discovered the two elements radium and polonium would be Marie Curie in 1898.

Hope this helps!
6 0
4 years ago
Suppose a 63-kg boy and a 40-kg girl use a massless rope in a tug-of-war on an icy, resistance-free surface. If the acceleration
kvasek [131]

Answer:

a₂ = 1.9 m/s²

Explanation:

Newton's third law or principle of action and reaction :

Force of the boy on the girl = -  Force of the girl on the boy

Fbg = - Fgb  Formula (1)

Newton's second law

∑F = m*a Formula (2)

∑F : algebraic sum of the forces in Newton (N)  

m : mass in kilograms (kg)

a : acceleration in meters over second square (m/s²)

Newton's second law to the girl

m₁ : girl mass

a₁ : acceleration of the girl toward the boy

∑F = m₁*a₁

Fbg= (40kg)*(3 m/s²)

Fbg = 120 N

Newton's second law to the boy

m₂: boy mass

a₂ : acceleration of the boy toward the girl

∑F = m₂*a₂

Fgb = (63)*a₂

120 = (63)*a₂

a₂ = 120 / (63)

a₂ = 1.9 m/s²

3 0
3 years ago
1.) A projectile is launched at 32.1 m/s and 52.6 º above the horizontal. Determine the:
Mandarinka [93]

Answer:

a.) Maximum height of the projectile. =32.5m

b.) The time it takes to reach the maximum height=2.6s

c.) Time of flight=2.6s

d.) Range=99.5m

Explanation:

5 0
3 years ago
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