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Fiesta28 [93]
2 years ago
13

HELP ME!!! NO LINKS!!! Compare and Contrast the scientific definitions of theory and law. Explain why the first law of thermodyn

amics is not considered to be a theory.
Physics
1 answer:
Nataly_w [17]2 years ago
3 0
The date the model was published.

The use of “laws” originated prior to science splitting from natural philosophy. There’s an implicit assumption that God as the creator laid down both moral and natural laws, with the theologian concerned with the former and the natural philosopher concerned with the latter.

“Theory” begins to take hold in the late 1700s and, very roughly speaking, is used to describe more complex models. “Law” eventually became nearly archaic, although still used to describe very pithy models (Amdahl’s Law, Gustafson’s Law).

The word “model” is gradually superseding both of them.

People have tried to come up with hard-and-fast rules to distinguish them, but scientists are unruly beasts, and use whatever language suits them in the moment.
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A person jogs 4.0 km in 32 minutes, then 2.0 km in 22 minutes, and finally 1.0 km in 16 minutes. What is the jogger's average sp
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an athlete whirls an 8.71 kg hammer tied to the end of a 1.5 m chain in a simple horizontal circle where you should ignore any v
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Answer:

T = 692.42 N

Explanation:

Given that,

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Length of the chain to which an athlete whirls the hammer, r = 1.5 m

The angular sped of the hammer, \omega=1.16\ rev/s=7.28\ rad/s

We need to find the tension in the chain. The tension acting in the chain is balanced by the required centripetal force. It is given by the formula as follows :

F=m\omega^2r\\\\=8.71\times (7.28)^2\times 1.5\\\\=692.42\ N

So, the tension in the chain is 692.42 N.

5 0
3 years ago
How much fuel dose it take to get a rocket to orbit the earth?
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if you have a mass of 55 kg and you are standing 3 meters away from your car, which has a mass of 1234 kg, how strong is the for
bagirrra123 [75]

Gravitational force between two masses is given by formula

F = \frac{Gm_1m_2}{r^2}

here we know that

m_1 = 55 kg

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G = 6.67 \times 10^{-11} Nm^2/kg^2

now from the above equation we will have

F = \frac{(6.67 \times 10^{-11})(55)(1234)}{3^2}

F = 5.03 \times 10^{-7}N

so above is the gravitational force between car and the person

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