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umka2103 [35]
2 years ago
9

Write 15 and 40 ratio simplest form

Mathematics
1 answer:
alexandr402 [8]2 years ago
5 0

Answer:

15:40

Step-by-step explanation:

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The mark up on an item is $3.75. If the mark up is 35%, what was the original price? Round
oksian1 [2.3K]

Answer:

$10.71

Step-by-step explanation:

\frac{3.75}{y} =\frac{35}{100}

y × 35 = 3.75 × 100

35y = 375

35y ÷ 35 = 375 ÷ 35

y=10\frac{5}{7}

y = 10.7142857143

10.7142857143 round to 10.71

5 0
3 years ago
Complete the square to solve 4x2 + 24x = 4.
igomit [66]

Answer:

x = - 3 ± \sqrt{10}

Step-by-step explanation:

Given

4x² + 24x = 4 ( divide through by 4 )

x² + 6x = 1

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(3)x + 9 = 1 + 9

(x + 3)² = 10 ( take the square root of both sides )

x + 3 = ± \sqrt{10} ( subtract 3 from both sides )

x = - 3 ± \sqrt{10}

8 0
3 years ago
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Elijah and 2 of his friends are each paid $20 per afternoon
aleksklad [387]
300 all together but 100 solo
6 0
3 years ago
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Please help!!!!!!!!!!!
liq [111]
It should be this y=1/2x+3
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3 years ago
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The amount A of the radioactive element radium in a sample decays at a rate proportional to the amount of radium present. Given
slavikrds [6]

Answer:

a) \frac{dm}{dt} = -k\cdot m, b) m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }, c) m(t) = 10\cdot e^{-\frac{t}{2438.155} }, d) m(300) \approx 8.842\,g

Step-by-step explanation:

a) Let assume an initial mass m decaying at a constant rate k throughout time, the differential equation is:

\frac{dm}{dt} = -k\cdot m

b) The general solution is found after separating variables and integrating each sides:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }

Where \tau is the time constant and k = \frac{1}{\tau}

c) The time constant is:

\tau = \frac{1690\,yr}{\ln 2}

\tau = 2438.155\,yr

The particular solution of the differential equation is:

m(t) = 10\cdot e^{-\frac{t}{2438.155} }

d) The amount of radium after 300 years is:

m(300) \approx 8.842\,g

4 0
3 years ago
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