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trapecia [35]
2 years ago
7

Which of the following is not a use of radioactive isotopes?

Chemistry
2 answers:
ANEK [815]2 years ago
8 0

Answer:

i belive the answer you are looking for is A.. hope this helps!

Explanation:

im not really 100% certain of this answer due to the fact i am a little rusty.

madreJ [45]2 years ago
5 0
Its A ‏ Believe me I got it on the test
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How many p-orbitals are occupied in a Ar atom?
Orlov [11]

Answer:

6

Explanation:

p orbital can hold up to six electron. Argon electron configuration will be 1s²2s²2p⁶3s²3p⁶

6 0
2 years ago
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The role of pigments both in capturing light energy and in converting it to the chemical energy of ATP and NADPH.
Aleonysh [2.5K]

Answer:

The explanation of the processes in which pigments are involved (capturing light and forming ATP and NADPH) is given in the following paragraphs)

Explanation:

Pigments are molecules with the capacity of absorbing light. Each pigment captures light of a specific wavelength. Plants contain different types of pigments like chlorophylls, xanthophylls, carotenoids, and others.

Chloroplasts (organelles present in cells of plants), contain pigmants that absorb solar radiation, triggering a series of reactions collectively known as photosynthesis. When light incides on a pigment, an electron of this molecules is excitated, goes into another level of energy and starts to pass through a series of carrier molecules to finally to a final aceptor of electrons. During this transport, part of the energy contained in the electron is used to generates a hydrogen gradient that provides energy. As a result of these processes, a molecule that is called  NADP+ accepts two electrons and an hydrogen to form NADPH, while another molecule known as ADP captures  an atom of phosphorous and gives rise to ATP (through the action of a protein called ATP sintase)..

7 0
2 years ago
Daniel is conducting an experiment on magnetic objects. He completes more than one trial. Why is it important for Daniel to do t
Luba_88 [7]

Answer:The conclusion is less accurate.

Explanation:

Feb 17, 2021 — He completes more than one trial. Why is it important for Daniel to do this?

4 0
2 years ago
Can someone help me please
lesantik [10]
It is an endothermic reaction because the products hAve more heat than the reactions so it was a gain of heat which makes the enthalpy Change positive !
4 0
3 years ago
N₂O(g) + 3 H₂(g) N₂H4(1) + H₂O(1) AH = -317 kJ/mol
docker41 [41]

Answer:

A

Explanation:

Recall that Δ<em>H</em> is the sum of the heats of formation of the products minus the heat of formation of the reactants multiplied by their respective coefficients. That is:


\displaystyle \Delta H^\circ_{rxn} = \sum \Delta H^\circ_{f} \left(\text{Products}\right) - \sum \Delta H^\circ_{f} \left(\text{Reactants}\right)

Therefore, from the chemical equation, we have that:


\displaystyle \begin{aligned} (-317\text{ kJ/mol}) = \left[\Delta H^\circ_f \text{ N$_2$H$_4$} +  \Delta H^\circ_f \text{ H$_2$O}  \right]   -\left[3 \Delta H^\circ_f \text{ H$_2$}+\Delta H^\circ_f \text{ N$_2$O}\right] \end{aligned}

Remember that the heat of formation of pure elements (e.g. H₂) are zero. Substitute in known values and solve for hydrazine:

\displaystyle \begin{aligned} (-317\text{ kJ/mol}) & = \left[ \Delta H^\circ _f \text{ N$_2$H$_4$} + (-285.8\text{ kJ/mol})\right] -\left[ 3(0) + (82.1\text{ kJ/mol})\right] \\ \\ \Delta H^\circ _f \text{ N$_2$H$_4$} & = (-317 + 285.8 + 82.1)\text{ kJ/mol} \\ \\ & = 50.9\text{ kJ/mol} \end{aligned}

In conclusion, our answer is A.

5 0
2 years ago
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