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2 years ago

Which of the following is not a use of radioactive isotopes?

Chemistry

2 answers:

ANEK [815]2 years ago

8 0

Answer:

i belive the answer you are looking for is A.. hope this helps!

Explanation:

im not really 100% certain of this answer due to the fact i am a little rusty.

madreJ [45]2 years ago

5 0

Its A ‏ Believe me I got it on the test

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The strongest light left over from the big bang is called background radiation and was given off as which type of wave?

Sonja [21]

It would be Microwaves. The cosmic microwave background (CMB, CMBR), in Big Bang cosmology, is electromagnetic radiation as a remnant from an early stage of the universe, also known as "relic radiation".

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3 years ago

How many moles are in 23.8 g of sulfur dioxide

Yuki888 [10]

Answer:

0.371

Explanation:

number of moles = mass / Ar

= 23.8g / 32.1 + (16.0 × 2)

= 0.37129485179 = 0.371 (3 s.f).

hope it helps :)

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2 years ago

Give the volume indicated. Be sure to include all significant figures.<br> 9.2<br> 9.16<br> 9.26

Gemiola [76]

Answer:

The volume indicated would be closest to 9.16

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3 years ago

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If a reaction mixture contains only n 2o and no2 at partial pressures of 1.0 atm each the reaction will be spontaneous until som

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3 years ago

A container of N2O3(g) has a pressure of 0.265 atm. When the absolute temperature of the N2O3(g) is tripled, the gas completely

Rzqust [24]

Answer:

1.59 atm

Explanation:

The reaction is:

$N_{2}O_{3}(g) - - -> NO_{2}(g)+NO(g)$

The dalton's law tell us that the total pressure of a mixture of gases is the sum of the partial pressure of every gas.

So after the reaction the total pressure is:

$P_{total}=P_{NO_{2}}+P_{NO}$

we don't include $N_{2}O_{3}$ because it decomposed completely.

Assuming ideal gases

PV=nRT

P= pressure, V= volume of the container, n= mol of gas, R=constant of gases and T=temperature.

so moles of $N_{2}O_{3}$ is:

$n_{N_{2}O_{3}}=\frac{P_{1}V}{RT_{1}}$

from the reaction stoichiometry (1:1) we have that after the reaction the number of moles of each product is the same number of moles of $N_{2}O_{3}$ .

$n_{NO_{2}}=\frac{P_{1}V}{RT_{1}}$