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sleet_krkn [62]
3 years ago
14

PLEASE HELP IM REALLY STRESSED OUT AND I JUST NEED SOMEONE TO DO THIS FOR ME! IK ITS ALOT SORRY! In this task, you'll determine

whether a reaction between baking soda and citric acid is an endothermic reaction and whether it can be used in a cold pack. Estimated time to complete: 15 minutes Use this information to answer the questions that follow: To begin the experiment, Xavier washed his hands and put on safety goggles. He then measured 120 milliliters of tap water, 2.5 milliliters of baking soda, and 2.5 milliliters of citric acid. The initial temperature of the water was 23.5°C. Next Xavier added the baking soda and citric acid to the water. The mixture immediately began to bubble vigorously, which lasted for about 30 seconds. The new temperature of the mixture was 17.7°C.
Part A: is a chemical reaction taking place during Xavier's experiment? How do you know?
Part B: Did the chemical reaction absorb or release energy? How do you know?
Part C: Could this chemical reaction be used inside a cold pack or inside a container designed to keep a drink cold? Justify your answer.
​
Chemistry
1 answer:
Burka [1]3 years ago
7 0

Answer:

The reaction is endothermic

Part A: Yes because there is an immediate reaction of bubbling vigorously.

Part B: It releases energy because when the compounds are added together they are immediately releasing it by bubbling and turning cold.

Part C: Yes because the liquids inside when combined give off coldness that makes the liquid temperature decrease to use this chemical reaction could definitely be used to keep something cold

Explanation:

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_AI + _HCI —> _H2 + _AlCl3
SOVA2 [1]

Hey there!

Al + HCl → H₂ + AlCl₃

Balance Cl.

1 on the left, 3 on the right. Add a coefficient of 3 in front of HCl.

Al + 3HCl → H₂ + AlCl₃

Balance H.

3 on the left, 2 on the right. We have to start by multiplying everything else by 2.

2Al + 3HCl → 2H₂ + 2AlCl₃

Now we have 2 on the right and 4 on the left. Change the coefficient in front of HCl from 3 to 4.

2Al + 4HCl → 2H₂ + 2AlCl₃

Now, for Cl, we have 4 on the left and 6 on the right. Change the coefficient in front of HCl again from 4 to 6.

2Al + 6HCl → 2H₂ + 2AlCl₃

Now, our H is unbalanced again. 6 on the left, 4 on the right. Change the coefficient in front of H₂ from 2 to 3.

2Al + 6HCl → 3H₂ + 2AlCl₃  

Balance Al.

2 on the left, 2 on the right. Already balanced.

Here is our final balanced equation:

2Al + 6HCl → 3H₂ + 2AlCl₃  

Hope this helps!

7 0
3 years ago
Harvey kept a balloon with a volume of 348 milliliters at 25.0˚C inside a freezer for a night. When he took it out, its new volu
ad-work [718]

Initial volume of the balloon = V_{1}= 348 mL

Initial temperature of the balloon T_{1} = 25.0^{0}C + 273 = 298 K

Final volume of the balloon V_{2} = 322 mL

Final temperature of the balloon = T_{2} = ?

According to Charles law, volume of an ideal gas is directly proportional to the temperature at constant pressure.

\frac{V_{1} }{T_{1} } =\frac{V_{2} }{T_{2} }

On plugging in the values,

\frac{348mL}{298 K} =\frac{322 mL}{T_{2} }

T_{2} =276 K

Therefore, the temperature of the freezer is 276 K

5 0
3 years ago
How much force is needed to accelerate a 66 kg skier at 2 m/sec2
alexgriva [62]

Answer:

132N

Explanation:

F=ma

F=66×2

F=132N

7 0
3 years ago
You want to create 14.0 g of copper to meld into a piece of jewelry. You
Yuki888 [10]

Answer:

3.4g of Al

Explanation:

you would need to start with 3.4 g of Al

3 0
3 years ago
Which of the following statements does NOT describe the anomeric carbon? A. This carbon is attached to two oxygens. B. This carb
MaRussiya [10]

Answer:

The answer is E. All of the statements describe the anomeric carbon.

Explanation:

When a sugar switches from its open form to its ring form, the carbon from the carbonyl (aldehyde if it is an aldose, or a ketone in the case of a ketose) suffers a nucleophilic addition by one of the hydroxyls in the chain, preferably one that will form a 5 or 6 membered ring after the reaction.

As such, the anomeric carbon will have two oxygens attached (The original one and the one that bonded when the ring closed).

It will be chiral, given that it has 4 different groups attached. (-OR,-OH,-H and -R, where R is the carbon chain).

The hydroxyl group can be in any position (Above of below the ring), depending on with side the addition took place. (See attachment)

It is the carbon of the carbonyl in the open-chain form of the sugar, because it is the only one that can react with the Hydroxyls.

8 0
3 years ago
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