Answer:
Jeweler B = more accurate
Jeweler A = more precise
Error:
0.008, 0
% error :
0.934% ; 0
Explanation:
Given that:
True mass of nugget = 0.856
Jeweler A: 0.863 g, 0.869 g, 0.859 g
Jeweler B: 0.875 g, 0.834 g, 0.858 g
Official measurement (A) = 0.863 + 0.869 + 0.859 = 2.591 / 3 = 0.864
Official measurement (B) = 0.875 + 0.834 + 0.858 = 2.567 / 3 = 0.8556
Accuracy = closeness of a measurement to the true value
Accuracy = true value - official measurement
Jeweler A's accuracy :
0.856 - 0.864 = - 0.008
Jeweler B's accuracy :
0.856 - 0.856 = 0.00
Therefore, Jeweler B's official measurement is more accurate as it is more close to the true value of the gold nugget.
However, Jeweler A's official measurement is more precise as each Jeweler A's measurement are closer to one another than Jeweler B's measurement which are more spread out.
Error:
Jeweler A's error :
0.864 - 0.856 = 0.008
% error =( error / true value) × 100
% error = (0.008/0.856) × 100% = 0.934%
Jeweler B's error :
0.856 - 0.856 = 0 ( since the official measurement as been rounded to match the decimal representation of the true value)
% error = 0%
1: it is +2
2: it is +6
(Make this brainliest answer please)
Answer:
0.0845 M
Explanation:
First we <u>convert 4.27 grams of potassium iodide into moles</u>, using its <em>molar mass</em>:
- Molar Mass of KI = 166 g/mol
- 4.27 g ÷ 166 g/mol = 0.0257 mol
Now we <u>calculate the molarity of the solution</u>, using <em>the number of moles and the given volume</em>:
- Molarity = moles / liters
- Molarity = 0.0257 mol / 0.304 L = 0.0845 M
Answer:
D. Strong nuclear force, electrostatic force, weak nuclear force, gravitational force
Answer : The mass of
required is, 166.4 grams.
Explanation :
First we have to calculate the moles of nitrogen gas.
Using ideal gas equation:

where,
P = Pressure of
gas = 1.00 atm
V = Volume of
gas = 113 L
n = number of moles
= ?
R = Gas constant = 
T = Temperature of
gas = 
Putting values in above equation, we get:


Now we have to calculate the moles of sodium azide.
The balanced chemical reaction is,

From the balanced reaction we conclude that
As, 3 mole of
produced from 2 mole of 
So, 3.84 moles of
produced from
moles of 
Now we have to calculate the mass of 

Molar mass of
= 65 g/mole

Therefore, the mass of
required is, 166.4 grams.