Answer:
As per Coulomb's law we know that force between two charges is given as
F = \frac{kq_1q_2}{r^2}F=
r
2
kq
1
q
2
here we know that
q_1 = 2.5 \times 10^{-6} Cq
1
=2.5×10
−6
C
q_2 = -5.0 \times 10^{-6} Cq
2
=−5.0×10
−6
C
r = 0.0050 mr=0.0050m
now from above formula we will have
F = \frac{(9 \times 10^9)(2.5 \times 10^{-6})(5 \times 10^{-6})}{(0.0050)^2}F=
(0.0050)
2
(9×10
9
)(2.5×10
−6
)(5×10
−6
)
F = 4500 NF=4500N
so they will attract towards each other as they are opposite in nature with force F = 4500 N
