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forsale [732]
2 years ago
11

HELP EASY PHYSICS QUESTION 1.A ball at rest is dropped from the top of an inclined plane at a height of 50 cm. What is the speed

of the ball when it reaches the bottom of the plane? a.3.13 m/s b.4.9 m/s c.9.8 m/s d.31.3 m/s 2. A 25 kg crate is moved through a distance of 4 m by a horizontal force of 60 N. What is the work done by the frictional force in moving the crate if the coefficient of kinetic friction is 0.2? a.240 J b.-240 J c.-196 J d.196 J
Physics
1 answer:
dexar [7]2 years ago
7 0

Answer:

45

Explanation:

it,s because of addition

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An unstretched spring has a length of 10. centimeters. When the spring is stretched by a force of 16 newtons, its length is incr
Fed [463]

Answer:

The spring constant of this spring  is 200 N/m.

Explanation:

Given:

Original unstretched length of the spring (x₀) = 10 cm =0.10 m [1 cm =0.01 m]

Stretched length of the spring (x₁) = 18 cm = 0.18 cm

Force acting on the spring (F) = 16 N

Spring constant of the spring (k) = ?

First let us find the change in length of the spring or the elongation caused in the spring due to the applied force.

So, Change in length = Final length - Initial length

\Delta x = x_1-x_0=0.18-0.10=0.08\ m

Now, restoring force acting on the spring is directly related to its elongation or compression as:

F=k\Delta x

Rewriting in terms of 'k', we get:

k=\dfrac{F}{\Delta x}

Now, plug in the given values and solve for 'k'. This gives,

k=\frac{16\ N}{0.08\ m}\\\\k=200\ N/m

Therefore, the spring constant of this spring  is 200 N/m.

5 0
2 years ago
Hi free ponits hehehehhehbhrgivudksjbtyuvwijfe
Vilka [71]

Answer:

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Explanation:

3 0
2 years ago
Read 2 more answers
A boat heads north at 30 mph while a steamer heads east at 40 mph at the same time. When is the distance between them 50 mi? Ans
Reil [10]

Answer:

1 hour

Explanation:

Speed of the first boat = 30 mph

Speed of the second = 40 mph

The boats will cover different distances but the time taken will be the same.

Time taken by the boats = t

Distance = Speed × Time

Distance covered by the first boat = 30t

Distance covered by the second boat = 40t

Distance between the boats = 50 mi

From the Pythagoras theorem

\sqrt{(30t)^2+(40t)^2}=50\\\Rightarrow \sqrt{2500t^2}=50\\\Rightarrow 50t=50\\\Rightarrow t=\frac{50}{50}=1\ hour

Time taken by the boats when they are 50 mi away is 1 hour

7 0
2 years ago
How can you measure the distance an object has moved?
Naily [24]

You must observe the object twice.

-- Look at it the first time, and make a mark where it is.

-- After some time has passed, look at the object again, and
make another mark at the place where it is.

-- At your convenience, take out your ruler, and measure the
distance between the two marks.

What you'll have is the object's "displacement" during that period
of time ... the distance between the start-point and end-point. 
Technically, you won't know the actual distance it has traveled
during that time, because you don't know the route it took.


8 0
3 years ago
A meteoroid is in a circular orbit 600 km above the surface of a distant planet. The planet has the same mass as Earth but has a
AVprozaik [17]
<h2>Answer:</h2><h2>The acceleration of the meteoroid due to the gravitational force exerted by the planet = 12.12 m/s^{2}</h2>

Explanation:

A meteoroid is in a circular orbit 600 km above the surface of a distant planet.

Mass of the planet = mass of earth = 5.972 x 10^{24} Kg

Radius of the earth = 90% of earth radius = 90% 6370 = 5733 km

The acceleration of the meteoroid due to the gravitational force exerted by the planet = ?

By formula, g = \frac{GM}{r^{2} }

where g is the acceleration due to the gravity

G is the universal gravitational constant = 6.67 x 10^{-11} m^{3} kg^{-1} s^{-2}

M is the mass of the planet

r is the radius of the planet

Substituting the values, we get

g =  \frac{(6.67 * 10^{-11}) (5.972 * 10^{24})  }{5733^{2} }

g = 12.12 m/s^{2}

The acceleration of the meteoroid due to the gravitational force exerted by the planet = 12.12 m/s^{2}

6 0
3 years ago
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