Momentum= mass*velocity=2000*35=70,000 kg m/s
Because the masses that you give are for blocks that are 1 cubic meter in volume, they also serve as the densities for the two metals that you are comparing.
<span>mass = density*volume </span>
<span>volume = (4/3)*pi*r^3 </span>
<span>volume of iron sphere = (4/3)*3.14*0.0201^3 = 3.40*10^-5 m^3 </span>
<span>mass of iron sphere = 7860* 3.40*10^-5 m^3 = 0.27 kg = mass of Aluminum Sphere </span>
<span>Volume of Al Sphere = 0.27/2700 = 9.90*10^-5 m^3 </span>
<span>Radius = cube root (volume / (4/3) / pi) = 2.87 cm. </span>
<span>I did this using the MS calculator, and I'm not 100% sure on the numerical answer, but the process is what you need to do to solve the problem. You should double check my answer.
hope this helped :)
</span>
Answer: 0.56 m/s
Explanation:
hello, there is 25° inclination angle for the chute in the drawing. Thankfully, I know this problem. The conservation of momentum.
so there are X and Y components for the momentum in this problem. The Y component is not conserved as when the coal gets in the cart, the normal force exerted by the surface reduces it to 0.
Now, the X component is definitely conserved here.
so you have the momentum of the cart which is 440*0.5 added to the momentum of the chunk which is 150*0.8*cos(25°), that is the momentum before the coupling between the objects. Afterwards both objects will have the same velocity, so we write the equation like this:
Groundwater <span>Precipitation that sinks into the ground is called Groundwater.</span>
The correct formula for
this simple harmonic motion is:
x = (6.0) cos [ (3 pi) t +
pi/3 ]
A. Calculating for displacement
x at t = 2:
x =6.0 cos (19/3 pi)
x = 6 (0.5)
x = 3 m
<span>B. Velocity is equivalent
to the 1st derivative of the equation. v = dx / dt </span>
<span> Velocity v = dx/dt = -18 pi sin (3pi t + pi/3) </span>
v = - 18 pi sin (6pi +
pi/3)
v = 49.0 m/s
<span>C. Acceleration is the 2nd
derivative or the 1st derivative of velocity dv / dt</span>
Acceleration a = dv/dt = -54 pi^2 cos(3pi t + pi/3)
a = -54 pi^2 cos(3pi * 2 +
pi/3)
a = 386.34 m/s^2
D. Phase = pi/3
E. frequency f= 3pi/2pi =
1.5Hz
<span>F. period = 1/f = 1/1.5 = .6667sec </span>
