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stiks02 [169]
2 years ago
5

6. True or False? Cell phones, bridges, trees, and surfboards are all technological products.

Engineering
1 answer:
miss Akunina [59]2 years ago
7 0

Answer: The answer to that is false.

Explanation: Trees are a natural plant that doesn't need any technical equipment to grow. If trees weren't a part of the 4 items, then I'm pretty sure that the answer would've been true.

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3. In order to obtain your commercial driver's license (CDL) you must first:
Murljashka [212]
A and C is the answer to the question. Be 15 years old & get a permit
8 0
3 years ago
An asphalt concrete mixture includes 94% aggregate by weight. The specific gravities of aggregate and asphalt are 2.65 and 1.0,
garik1379 [7]

Answer:

2.0%

Explanation:

Percentage of aggregate = 94%

Specific gravity = 2.65

Specific gravity of asphalt = 1.9

Density of mix = 147pcf = 147lb/ft³

Total weight of mix: (volume = 1ft³)

= (147lb/ft³)(1ft³)

= 147lb

Percentage weight of asphalt in<u> mix:</u>

100% - 94%

= 6%

Weight of asphalt binders

= 6% x 147lb

= 8.82lb

Weight of aggregate in mix:

= 94% x 147

= 138.18lb

Specific weight of asphalt binder:

(Gab)(Yw)

Yw = specific Weight of water

= 62.4lb

Gab = specific gravity of asphalt binder

= 1.0

(62.4lb)(1.0)

= 62.4 lb/ft³

Volume of asphalt in binder:

8.82/62.4

= 0.14ft³

Specific weight of binder in mix:

2.65 x 62.4lb/ft³

= 165.36 lb/ft³

Volume of aggregate:

= 138.18/165.36

= 0.84ft³

Volume of void in the mix:

1ft³ - 0.84ft³ - 0.14ft³

= 0.02ft³

<u>The percentage of void in total mix:</u>

VTM = (0.02ft³/1ft³)100

= 2.0%

8 0
3 years ago
What process does a professional use to find an object’s position with respect to the camera?
shtirl [24]

Answer:

"D

Explanation:

5 0
3 years ago
Read 2 more answers
A piston-cylinder assembly contains 0.5 lb of water. The water expands from an initial state where p1 = 40 lbf/in.2 and T1 = 300
VARVARA [1.3K]

Answer:

W = 31.393 Btu

Explanation:

given data

piston-cylinder assembly contains water = 0.5 lb

p1 = 40 lbf/in² = 40 × 144 lbf/ft²

T1 = 300° F

p2 = 14.7 lbf/in² = 14.7  × 144 lbf/ft²

pv 1.2 = constant.

solution

we use here superheated table A 4E  to get value for p1 = 40 and t = 300

v1 = 11.04 ft³/lbm

so we know

P_2 \times V_2^{1.2} = P_1 \times V_1^{1.2}    ,...............1

14.7 \times V_2^{1.2} = 40 \times (11.04)^{1.2}

solve it we get

v2 = 25.425 ft³/lbm

and here

W = (\frac{P_1V_1 - P_2V_2}{n-1}) m   ...............2

put here value we get

W = (\frac{40\times 144\times (11.04) -14.7 \times 144\times (25.425) }{1.2-1})0.5  

solve it we get

W = 31.393 Btu

5 0
3 years ago
The fan pressure differential gage on an air handler reads 12 cm H2O. What is this pressure differential in kiloPascals
Deffense [45]

Answer:

1.18\ \text{kPa}

Explanation:

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

h = Height of reading = 12 cm

\rho = Density of water = 1000\ \text{kg/m}^3

Pressure due to height difference is given by

P=\rho gh\\\Rightarrow P=1000\times 9.81\times 12\times 10^{-2}\\\Rightarrow P=1177.2\ \text{Pa}=1.1772\ \text{kPa}\approx 1.18\ \text{kPa}

The pressure differential is 1.18\ \text{kPa}.

4 0
3 years ago
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