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Burka [1]
2 years ago
11

Countercurrent Flow

Chemistry
1 answer:
Nikitich [7]2 years ago
7 0

Answer: All options (I, II, III, IV, V)

Explanation: The answer is all options because they never reach equilibrium or intersect at a region as the both decrease at the same rate.

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Cells are made of organelles, specialized structures at each perform specific functions that help the cell maintain homeostasis.
Lynna [10]

Answer:

B and d and E

Explanation:

6 0
2 years ago
Ejemplos de magnitudes escalares en la vida cotidiana?<br>​
Doss [256]

Answer:

Temperatura. Es una magnitud escalar ya que un valor numérico la define por completo. ...

Presión. ...

Longitud. ...

Energía. ...

Masa. ...

Tiempo. ...

Área. ...

Volumen.

Explanation:

3 0
3 years ago
What kind of plant growth hormone to regular plant growth. We dissolve 5.0 mg of the solution into 2.0 kg of water. What is the
In-s [12.5K]

Answer:

The dosage of the solution is 2.5 parts per million.

Explanation:

The solvent proportion in parts per million is equal to the ratio of solution in miligrams to ratio of water in miligrams multiplied by a million. (A kilogram is equivalent to a million miligrams) That is:

p.p.m. = \frac{5\,mg}{2000000\,mg}\times 1000000

p.p.m. = 2.5\, ppm

The dosage of the solution is 2.5 parts per million.

3 0
3 years ago
After mixing an excess PbCl2 with a fixed amount of water, it is found that the equilibrium concentration of Pb2 is
Tanzania [10]

Answer:

Ksp = 8.8x10⁻⁵

Explanation:

<em>Full question is:</em>

<em>After mixing an excess PbCl2 with a fixed amount of water, it is found that the equilibrium concentration of Pb2+ is 2.8 × 10–2 M. What is Ksp for PbCl2?</em>

<em />

When an excess of PbCl₂ is added to water, Pb²⁺ and Cl⁻ ions are produced following Ksp equilibrium:

PbCl₂(s) ⇄ Pb²⁺ + 2Cl⁻

Ksp = [Pb²⁺] [Cl⁻]²

If an excess of PbCl₂ was added, an amount of Pb²⁺ is produced (X) and twice Pb²⁺ is produced as Cl⁻ (2X):

Ksp = [X] [2X]²

Ksp = 4X³

As X is the amount of Pb²⁺ = 2.8x10⁻²M:

Ksp = 4(2.8x10⁻²)³

<h3>Ksp = 8.8x10⁻⁵</h3>
4 0
4 years ago
The 500kg concrete culvert has a mean radius of 0.5m. part a if the truck has an acceleration of 3m/s2, determine the culvert's
jarptica [38.1K]

<u>Given: </u>

Radius of culvert, r = 0.5 m

Tangential acceleration of the truck, a = 3 m/s2

<u>To determine:</u>

The angular acceleration, α

<u>Explanation:</u>

The tangential acceleration is related to the angular acceleration through the radius as:

a = rα

α = a/r = 3 ms⁻²/0.5 m = 6 s⁻²

Ans: The angular acceleration is 6 s⁻²


6 0
3 years ago
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