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1 year ago

Countercurrent Flow

Chemistry

1 answer:

Nikitich [7]1 year ago

7 0

Answer: All options (I, II, III, IV, V)

Explanation: The answer is all options because they never reach equilibrium or intersect at a region as the both decrease at the same rate.

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Glycerol (molar mass 92.09 g/mol) has been suggested for use as an alternative fuel. The enthalpy of combustion, Δ

victus00 [196]

The mass of glycerol to that would need to be combusted to heat 500.0g of water from 20.0°C to 100.0°C is; 9.32 grams.

We must establish the fact that energy is neither created nor destroyed.

Therefore, the amount of heat absorbed by water is equal to the amount of heat released by the combustion of glycerol.

Total heat absorbed by water, H(water) is;

Q(water) = m C (T2 - T1)

Q(water) = 500 × 4.184 × (100-20)

Q(water) = 167.36 kJ

Consequently, the quantity of heat evolved by the combustion of glycerol is;

Q(glycerol) = 167,360 J = n × ΔH°comb

where, n = no. of moles of glycerol.

167.36 kJ= n × 1654 kJ/mole

n = 167.36/1654

n = 0.1012 moles of glycerol.

Therefore, mass of glycerol combusted, m is;

m = n × Molar mass

m = 0.1012 × 92.09

m = 9.32 g.

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How much calcium can be recovered from 75.0g of calcium fluoride

7nadin3 [17]

38.46g

Explanation:

Given parameters:

Mass of CaF₂ = 75.0g

Unknown:

Mass of calcium that can be recovered = ?

Solution:

This is a mass percentage problem and we need to solve it accordingly.

To solve this problem;

Find the molar mass of CaF₂

Find the ratio between the molar mass of Ca and that of CaF₂

Multiply by the given mass

Molar mass of CaF₂ = 40 + (2 x 19) = 78g/mol

Mass of calcium = $\frac{40}{78}$ x 75 = 38.46g

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Mass percentage brainly.com/question/8170905

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