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azamat
3 years ago
15

A transformer has 90 turns in the primary coil and 9 turns in the secondary coil If the output voltage is 6 V, what is the input

voltage
Chemistry
1 answer:
Afina-wow [57]3 years ago
6 0

Answer:

60 V

Explanation:

From;

Vs/Vp = Ns/Np

Where;

Vs = voltage in the secondary coil = 6V

Vp = voltage in the primary coil= ??

Ns = number of turns in the secondary coil = 9

Np= number of turns in the primary coil = 90

6/Vp = 9/90

Vp= 90 * 6/9

Vp=  60 V

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Since the chemical reaction is 2CO + O₂ → 2CO₂ and the total bond energy of the products carbon dioxide CO₂ is 1,472 kJ.

Since from the chemical reaction, we have 2 moles of CO₂ which gives 1,472 kJ and there are two carbon-oxygen, C-O bonds in CO₂, then

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Rate constant for first-order kinetics: 0,05 [1/s]

Explanation:

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r = k [A]^{x} [B]^{y}

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For the kinetics of zero-order, the rate is apparently independent of the reactant concentration.

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<em>Rate Law:                                        rate= k[A]</em>

<em>Concentration -Time Equation:      ln[A]=ln[A]o - kt</em>

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  • ln[A]: natural logarithm of the concentration in the time <em>t </em>[M]
  • ln[A]o: natural logarithm of the initial concentration [M]
  • t: elapsed reaction time [s]

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t = 1 hour = 60 s

As we don't know the molar mass of the compound A, we can't convert the used concentration unit (mg/L) to molar concentration (M). So we'll solve the problem using mg/L as the concentration unit.

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we use:                        [A]=[A]o - Kt

we replace the data:   5 = 100 - K (60)

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we use:                                  ln[A]=ln[A]o - Kt

we replace the data:               ln(5)  = ln(100) - K (60)

we clear K:                                   K = [ln(100) - ln(5)] /60 (s)  = 0,05 [1/s]

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