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loris [4]
3 years ago
5

The condition where all forces acting on an object are balanced is called

Engineering
1 answer:
uranmaximum [27]3 years ago
4 0

Answer:

C) O Equilibrium

Explanation:

An object will only accelerate if there is a net or unbalanced force acting upon it.

You might be interested in
Select four geometric shapes that are commonly used by engineers in their designs.
stealth61 [152]

Answer:

Arc ,sphere ,line ,prism

Explanation:

  • Arc is used for semicircular or short term projects
  • Sphere is used for design of spherical surfaces or projects
  • Prism is used for creating buliding designs
  • Lines are especially used for creating roads, flyover design
3 0
2 years ago
A high-voltage transmission line carries 1 000 A at 700 kV for a distance of 100 miles. If the resistance per length in the wire
mamaluj [8]

Answer:

50 MW

Explanation:

We are given;

Current = 1000A

Voltage = 700 KV

Resistance per length = 0.5 Ω/mile

Length = 100 miles

The total resistance would be;

R=0.5 Ω/mile x 100 miles = 50Ω.

Now, the current is the same throughout the wire, but the voltage is only at the beginning of the line, and thus the current for the power equation is;

P = I²R

So;

P=(1000A)² x 50Ω.= 50,000,000W = 50MW

3 0
3 years ago
What is the basic concept of the finite element method.​
KIM [24]

Answer:

The FEM is a general numerical method for solving partial differential equations in two or three space variables (i.e., some boundary value problems). To solve a problem, the FEM subdivides a large system into smaller, simpler parts that are called finite elements.

5 0
2 years ago
Find the minimum diameter of a solid circular shaft if it has a maximum shear stress of 53 MPa and it is to transmit 28 kW of po
amid [387]

Answer:

d= 21.6 mm

Explanation:

Given that

P= 28 KW

τ = 53 MPa

N= 2516 RPM

We know that

P =\dfrac{2\pi NT}{60}

T =\dfrac{60\times P}{2\pi N}

By  putting the values

T =\dfrac{60\times 28\times 1000}{2\pi \times 2516}

T=106.27 N.m

We know that for solid shaft

\tau =\dfrac{16T}{\pi d^3}

53\times 10^6 =\dfrac{16\times 106.27}{\pi d^3}

d^3=\dfrac{16\times 106.27}{\pi \times 53\times 10^6 }

d=\left(\dfrac{16\times 106.27}{\pi \times 53\times 10^6 }\right)^{\frac{1}{3}}

d= 0.0216 m

d= 21.6 mm

8 0
3 years ago
NEED HELP WILL MARK BRAINLEST!!
Studentka2010 [4]
Size of font ok there u go
3 0
3 years ago
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