Answer:
Technician b is correct
Explanation:
Before adjusting drive-belt tension, it is very important to check the vehicle workshop manual for specified belt tension, so that you can match your reading against the specification in the vehicle's service manual. If the tension reading you have matches the suggested reading in the vehicle's service manual and the belt is not damaged then you do not need to proceed any further. But if the reading does not match, then you can adjust the belt tension.
Therefore, technician b is correct.
The statement "Visual perception is a mental process that is non selective" is false, it is a psychic function that allows the organism to capture, elaborate and interpret selective information that comes from the environment.
<h2>What is visual perception?</h2>
Visual perception is that inner sensation of apparent knowledge, resulting from a specific stimulus or light impression recorded by the eyes.
<h3>Characteristics of visual perception</h3>
- It incorporates the sensory stimuli received from objects, situations or events and converts them into a meaningful interpretation experience.
- It is an active process of the brain through which an external reality is created by transforming the light information captured by the eye.
Therefore, we can conclude that visual perception is the interpretation made by the brain of the different organisms of the stimuli received through the senses.
Learn more about visual perception here: brainly.com/question/10259599
solution from c hegg. hope it helps. see photos explanation
Answer:
![Q_{cv} = -1007.86kJ](https://tex.z-dn.net/?f=Q_%7Bcv%7D%20%3D%20-1007.86kJ)
Explanation:
Our values are,
State 1
![V=3m^3\\P_1=1bar\\T_1 = 295K](https://tex.z-dn.net/?f=V%3D3m%5E3%5C%5CP_1%3D1bar%5C%5CT_1%20%3D%20295K)
We know moreover for the tables A-15 that
![u_1 = 210.49kJ/kg\\h_i = 295.17kJkg](https://tex.z-dn.net/?f=u_1%20%3D%20210.49kJ%2Fkg%5C%5Ch_i%20%3D%20295.17kJkg)
State 2
![P_2 =6bar\\T_2 = 296K\\T_f = 320K](https://tex.z-dn.net/?f=P_2%20%3D6bar%5C%5CT_2%20%3D%20296K%5C%5CT_f%20%3D%20320K)
For tables we know at T=320K
![u_2 = 228.42kJ/kg](https://tex.z-dn.net/?f=u_2%20%3D%20228.42kJ%2Fkg)
We need to use the ideal gas equation to estimate the mass, so
![m_1 = \frac{p_1V}{RT_1}](https://tex.z-dn.net/?f=m_1%20%3D%20%5Cfrac%7Bp_1V%7D%7BRT_1%7D)
![m_1 = \frac{1bar*100kPa/1bar(3m^3)}{0.287kJ/kg.K(295k)}](https://tex.z-dn.net/?f=m_1%20%3D%20%5Cfrac%7B1bar%2A100kPa%2F1bar%283m%5E3%29%7D%7B0.287kJ%2Fkg.K%28295k%29%7D)
![m_1 = 3.54kg](https://tex.z-dn.net/?f=m_1%20%3D%203.54kg)
Using now for the final mass:
![m_2 = \frac{p_2V}{RT_2}](https://tex.z-dn.net/?f=m_2%20%3D%20%5Cfrac%7Bp_2V%7D%7BRT_2%7D)
![m_2 = \frac{1bar*100kPa/6bar(3m^3)}{0.287kJ/kg.K(320k)}](https://tex.z-dn.net/?f=m_2%20%3D%20%5Cfrac%7B1bar%2A100kPa%2F6bar%283m%5E3%29%7D%7B0.287kJ%2Fkg.K%28320k%29%7D)
![m_2 = 19.59kg](https://tex.z-dn.net/?f=m_2%20%3D%2019.59kg)
We only need to apply a energy balance equation:
![Q_{cv}+m_ih_i = m_2u_2-m_1u_1](https://tex.z-dn.net/?f=Q_%7Bcv%7D%2Bm_ih_i%20%3D%20m_2u_2-m_1u_1)
![Q_{cv}=m_2u_2-m1_u_1-(m_2-m_1)h_i](https://tex.z-dn.net/?f=Q_%7Bcv%7D%3Dm_2u_2-m1_u_1-%28m_2-m_1%29h_i)
![Q_{cv} = (19.59)(228.42)-(3.54)(210.49)-(19.59-3.54)(295.17)](https://tex.z-dn.net/?f=Q_%7Bcv%7D%20%3D%20%2819.59%29%28228.42%29-%283.54%29%28210.49%29-%2819.59-3.54%29%28295.17%29)
![Q_{cv} = -1007.86kJ](https://tex.z-dn.net/?f=Q_%7Bcv%7D%20%3D%20-1007.86kJ)
The negative value indidicates heat ransfer from the system