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IgorC [24]
3 years ago
10

What factors need to be considered when building housing on a waterway

Engineering
2 answers:
vesna_86 [32]3 years ago
8 0

Answer:

flooding

Explanation:

kotykmax [81]3 years ago
7 0

Answer:

Flooding

Explanation:

.

You might be interested in
In a river reach, the rate of inflow at any time is 350 cfs and the rate of outflow is 285 cfs. After 90 min, the inflow and out
Semenov [28]

Answer:

change in storage =  -310,500 ft^3

intital storage= 3.67 acre ft

Explanation:

Given data:

Rate of inflow = 350 cfs

Rate of outflow = 285 cfs

After 90 min,  rate of inflow = 250 cfs

Rate of outflow = 200 cfs

final storage = 10.8 acre-ft

calculating the average inflow and outflow

average inflow  = \frac{(350+250)}{2} = 300 cfs

average outlow  = \frac{(285+200)}{2} = 242.5 cfs

total amount of water drain during the period of one hour

= (average outflow - average inflow) *60*90

= (242.5 - 300)*60*90 = -310,500

change in storage is calculate as

= -310,500 ft^3

in cubic meter

= -310500/35.315 = 8792.30 cm^3

in acre-ft

= -310,500/43560 = 7.13 acre ft

initial storage = 10.8 - 7.13 = 3.67 acre ft

3 0
3 years ago
A tool used to drive and pull out nails​
Tju [1.3M]

Answer:

claw hammer

Explanation:

A claw hammer is a tool used for driving nails into an object or pulling nails from some other object.

6 0
2 years ago
Read 2 more answers
1. Implement the k-means clustering algorithm either in Java or Python. • The program should be executable with at least 3 param
givi [52]

Answer:

The code for this Question in Python is as follows:

matplotlib inline

from copy import deepcopy

import numpy as np

import pandas as pd

from matplotlib import pyplot as plt

plt.rcParams['figure.figsize'] = (16, 9)

plt.style.use('ggplot')

# Importing the dataset

data = pd.read_csv('xclara.csv')

print(data.shape)

data.head()

# Getting the values and plotting it

f1 = data['V1'].values

f2 = data['V2'].values

X = np.array(list(zip(f1, f2)))

plt.scatter(f1, f2, c='black', s=7)

# Number of clusters

k = 3

# X coordinates of random centroids

C_x = np.random.randint(0, np.max(X)-20, size=k)

# Y coordinates of random centroids

C_y = np.random.randint(0, np.max(X)-20, size=k)

C = np.array(list(zip(C_x, C_y)), dtype=np.float32)

print(C)

# To store the value of centroids when it updates

C_old = np.zeros(C.shape)

# Cluster Lables(0, 1, 2)

clusters = np.zeros(len(X))

# Error func. - Distance between new centroids and old centroids

error = dist(C, C_old, None)

# Loop will run till the error becomes zero

while error != 0:

   # Assigning each value to its closest cluster

   for i in range(len(X)):

       distances = dist(X[i], C)

       cluster = np.argmin(distances)

       clusters[i] = cluster

   # Storing the old centroid values

   C_old = deepcopy(C)

   # Finding the new centroids by taking the average value

   for i in range(k):

       points = [X[j] for j in range(len(X)) if clusters[j] == i]

       C[i] = np.mean(points, axis=0)

   error = dist(C, C_old, None)

# Initializing KMeans

kmeans = KMeans(n_clusters=4)

# Fitting with inputs

kmeans = kmeans.fit(X)

# Predicting the clusters

labels = kmeans.predict(X)

# Getting the cluster centers

C = kmeans.cluster_centers_

fig = plt.figure()

ax = Axes3D(fig)

ax.scatter(X[:, 0], X[:, 1], X[:, 2], c=y)

ax.scatter(C[:, 0], C[:, 1], C[:, 2], marker='*', c='#050505', s=1000)

4 0
4 years ago
The diesel fuel cooler is being discussed. Technician A says that high-pressure fuel systems generate a lot of heat. Technician
GuDViN [60]

Answer:

Both the technicians are correct.

Explanation:

As the pressure increases the temperature will also increase in accordance with the Boyle's law hence greater amount of heat is formed.

Pressure\propto Temperature

When the temperature increases the intermolecular spaces increase as the molecules of the fuel gain energy and their kinetic energy increases. This is limited to temperatures below dissociation/combustion temperature of diesel .

8 0
3 years ago
Two vertical parallel plates are spaced 0.01 ft apart. If the pressure decreases at a rate of 60 psf/ft in the vertical z-direct
Whitepunk [10]

Answer:

umax = 0.1259ft/s

Explanation:

Given:

•Distance between plates, B = 0.01ft

•Pressure difference decrease, \frac{dp}{dz}=60ps/ft

•Fluid viscosity, u = 10^-³lbf-s/ft²

Specific gravity, S = 0.80

Max velocity in the z-direction will be:

u_max= [\frac{B^2y}{8u}]\frac{dh}{ds}

But h = \frac{P}{y}+z

Substituting for h in the first equation, we have:

\frac{d}{dz}[\frac{p}{y}+z]

\frac{dh}{dz}=\frac{1}{y}\frac{dp}{ds}+\frac{dz}{dz}

= \frac{1}{0.8*62.4}(-60)+1

= -0.20192

Substituting dh/dz value in the first equation (umax), we have:

umax = \frac{0.01^2(0.8*62.4)}{8*10^-^3}(-0.20192)

umax = 0.1259ft/s

4 0
3 years ago
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