Answer:
The match
Explanation:
You can light both the lantern and the candle if you light the match first.
I don't know of this is a homework question, but I answered it anyway :)
Answer:
gauge pressure is 133 kPa
Explanation:
given data
initial temperature T1 = 27°C = 300 K
gauge pressure = 300 kPa = 300 × 10³ Pa
atmospheric pressure = 1 atm
final temperature T2 = 77°C = 350 K
to find out
final pressure
solution
we know that gauge pressure is = absolute pressure - atmospheric pressure so
P (gauge ) = 300 × 10³ Pa - 1 × 
Pa
P (gauge ) = 2 × Pa
so from idea gas equation
................1
so 
P2 = 2.33 × Pa
so gauge pressure = absolute pressure - atmospheric pressure
gauge pressure = 2.33 × - 1.0 ×
gauge pressure = 1.33 × Pa
so gauge pressure is 133 kPa
Answer:
path-dependent. However, if all heat transfer with surroundings is performed using a reversible heat transfer device (some type of reversible Carnot-type device), work can be performed by the heat transfer device during heat transfer to the surroundings. The net heat transferred to the surroundings and the net work done will be independent of the path. Demonstrate this by calculating the work and heat interactions for the system, the heat transfer device, and the sum for each of the following paths where the surroundings are at Tsurr = 273 K. The state change is from state 1, P1 = 0.1 MPa, T1 = 298 K and state 2, P2 = 0.5 MPa and T2 which will be found in part (a). CP = 7R/2. a. Consider a state change for an ideal gas in a piston/cylinder. Find T2 by an adiabatic reversible path. Find the heat and work such that no entropy is generated in the universe. This is path a. Sketch path a qualitatively on a P-V diagram. b. Now consider a path
Answer:
the minimum expected elastic modulus is 372.27 Gpa
Explanation:
First we put down the data in the given question;
Volume fraction 
= 0.84
Volume fraction of matrix material 
= 1 - 0.84 = 0.16
Elastic module of particle 
= 682 GPa
Elastic module of matrix material 
= 110 GPa
Now, the minimum expected elastic modulus will be;
= ( × ) / ( + )
so we substitute in our values
= (682 × 110 ) / ( [ 682 × 0.16 ] + [ 110 × 0.84] )
= ( 75,020 ) / ( 109.12 + 92.4 )
= 75,020 / 201.52
= 372.27 Gpa
Therefore, the minimum expected elastic modulus is 372.27 Gpa
