Answer:
C = 292 Mbps
Explanation:
Given:
- Signal Transmitted Power P = 250mW
- The noise in channel N = 10 uW
- The signal bandwidth W = 20 MHz
Find:
what is the maximum capacity of the channel?
Solution:
-The capacity of the channel is given by Shannon's Formula:
C = W*log_2 ( 1 + P/N)
- Plug the values in:
C = (20*10^6)*log_2 ( 1 + 250*10^-3/10)
C = (20*10^6)*log_2 (25001)
C = (20*10^6)*14.6096
C = 292 Mbps
Any collection of data or information that has been properly structured for quick search and retrieval by a computer is referred to as a database, often known as an electronic database.
<h3>What is electronic database?</h3>
- Databases are designed to make it easy to save, retrieve, edit, and delete data while carrying out various data-processing tasks. In response to queries, a database management system (DBMS) retrieves data from the database.
- Databases are briefly discussed after that. See computer science: Information systems and databases; information processing for a comprehensive explanation.
- A file or collection of files used to store a database.
- These files' contents can be divided up into records, each of which has one or more fields.
- The fundamental units of data storage are fields, and each field typically contains data related to one feature or attribute of the thing that the database is describing.
- Additionally, records are arranged into tables that contain details on the connections between their various fields.
- A database in the strict sense offers cross-referencing capabilities, despite the fact that the term "database" is used broadly to refer to any collection of information in computer files.
- Users can quickly search, rearrange, organize, and choose the fields in numerous records to access or produce reports on certain data aggregates using keywords and a variety of sorting instructions.
To Learn more About database Refer To :
brainly.com/question/518894
#SPJ1
Answer:
Power = 371.28 kW
Explanation:
Initial pressure, P1 = 5 bar
Final pressure, P2 = 1 bar
Initial temperature, T1 = 320°C
Final temperature, T2 = 160°C
Volume flow rate, V = 0.65m³/s
From steam tables at state 1,
h1 = 3105.6 kJ/kg, s1 = 7.5308 kJ/kgK
v1 = 0.5416 m³/kg
Mass flow rate, m = V/v1
m = 1.2 kg/s
From steam tables, at state 2
h2 = 2796.2 kJ/kg, s2 = 7.6597 kJ/kgK
Power developed, P = m(h1 - h2)
P = 1.2(3105.6-2796.2)
P = 371.28 kW
Complete Question
For some metal alloy, a true stress of 345 MPa (50040 psi) produces a plastic true strain of 0.02. How much will a specimen of this material elongate when a true stress of 411 MPa (59610 psi) is applied if the original length is 470 mm (18.50 in.)?Assume a value of 0.22 for the strain-hardening exponent, n.
Answer:
The elongation is 
Explanation:
In order to gain a good understanding of this solution let define some terms
True Stress
A true stress can be defined as the quotient obtained when instantaneous applied load is divided by instantaneous cross-sectional area of a material it can be denoted as 
.
True Strain
A true strain can be defined as the value obtained when the natural logarithm quotient of instantaneous gauge length divided by original gauge length of a material is being bend out of shape by a uni-axial force. it can be denoted as 
.
The mathematical relation between stress to strain on the plastic region of deformation is
Where K is a constant
n is known as the strain hardening exponent
This constant K can be obtained as follows
No substituting 
from the question we have
Making the subject from the equation above
From the definition we mentioned instantaneous length and this can be obtained mathematically as follows
Where
is the instantaneous length
is the original length
We can also obtain the elongated length mathematically as follows
