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3 years ago

What conversion factor would you use to convert grams to kilograms?

Chemistry

2 answers:

Natalija [7]3 years ago

4 0

Answer:

1kg=1000g

Explanation:

marusya05 [52]3 years ago

3 0

Since it’s 3 units over, you have to put 3 zeros behind the 1 to make it grams. So it would be 1kg is equal to 1000 grams. Or 1kg=1000g

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Plz answer question! Due Today!!! Question is in picture! Will make BRAINLIEST for first correct answer!!! No links plz!

iris [78.8K]

Answer:

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3 years ago

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A chemist prepares a solution of sodium thiosulfate by measuring out of sodium thiosulfate into a volumetric flask and filling t

marshall27 [118]

Mass of sodium thiosulfate $Na_{2}S_{2}O_{3}$ is 110. g

Volume of the solution is 350. mL

Calculating the moles of sodium thiosulfate:

$110. g Na_{2}S_{2}O_{3} * \frac{1 mol Na_{2}S_{2}O_{3}}{158.1 g Na_{2}S_{2}O_{3}}$ = 0.696 mol $Na_{2}S_{2}O_{3}$

Converting the volume of solution to L:

$350. mL * \frac{1 L}{1000 mL} = 0.350 L$

Finding out the concentration of solution in molarity:

$\frac{0.696 mol}{0.350 L} = 1.99 mol/L$

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3 years ago

Which of the following best describes an ecosystem in a California tide pool?

frosja888 [35]

Answer: i think your answer is The giant green anemones, the ochre sea stars, and the red octopuses because an ecosystem means all the organisms and the physical environment with which they interact. If not then your other option would be A a school of fluffy sculpins.

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2 years ago

What does it mean to optimize a solution ? How are solutions optimize

Romashka [77]

Question

What does it mean to optimize a solution?

To find out best possible solution for a given problem within the given constraint is generally termed as optimization

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To solve an optimization problem, begin by drawing a picture and introducing variables. Find an equation relating the variables. Find a function of one variable to describe the quantity that is to be minimized or maximized. Look for critical points to locate local extrema.

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3 years ago

The atomic masses of 151eu and 153eu are 150.919860 and 152.921243 amu, respectively. The average atomic mass of europium is 151

vitfil [10]

Answer:- The natural abundance of $^1^5^1_E_u$ is 0.478 or 47.8% and $^1^5^3_E_u$ is 0.522 or 52.2% .

Solution:- Average atomic mass of an element is calculated from the atomic masses of it's isotopes and their abundances using the formula:

Average atomic mass = mass of first isotope(abundance) + mass of second isotope(abundance)

We have been given with atomic masses for $^1^5^1_E_u$ and $^1^5^3_E_u$ as 150.919860 and 152.921243 amu, respectively. Average atomic mass of Eu is 151.964 amu.

Sum of natural abundances of isotopes of an element is always 1. If we assume the abundance of $^1^5^1_E_u$ as n then the abundance of $^1^5^3_E_u$ would be 1-n .

Let's plug in the values in the formula:

$151.964=150.919860(n)+152.921243(1-n)$