Answer:
energy required=-energy lost
energy lost=change in kinetic energy
EL=1/2 mv^2
True. Light can be described both as flow of particles and as an electromagnetic wave.
Answer:
176.4 meters
Explanation:
The first equation is for average velocity. The other three are the constant acceleration equations you'll need to know.
v = at + v₀
v² = v₀² + 2a(x − x₀)
x = x₀ + v₀ t + ½ at²
x is the final position
x₀ is the initial position
v is the final velocity
v₀ is the initial velocity
t is time
a is acceleration
Notice that the first equation is independent of position.
The second equation is independent of time.
The third equation is independent of final velocity.
So knowing which information you <em>don't</em> have will point you to which equation you should use.
Let's begin:
"Which one would be best to find the distance the object fell from free-fall if it fell for six seconds, assuming if fell in the absence of air resistance and it still hasn't hit the ground? Solve this problem and show all steps of work."
We want to find the distance (change in position). We're given the time (t = 6 s) and we're given the acceleration (free fall without air resistance, so a = -9.8 m/s²).
We aren't given the final velocity, so the equation we should use is the third one:
y = y₀ + v₀ t + ½ at²
Unfortunately, we aren't told the initial velocity, but if we assume that the object starts at rest, then v₀ = 0 m/s. Substituting all values:
y = y₀ + (0 m/s) (6 s) + ½ (-9.8 m/s²) (6 s)²
y − y₀ = -176.4 m
The displacement is -176.4 m. Distance is the magnitude of displacement, so we can say the object fell 176.4 meters.
In order to develop this problem it is necessary to use the concepts related to the conservation of both potential cinematic as gravitational energy,
Where,
M = Mass of Earth
m = Mass of Object
v = Velocity
r = Radius
G = Gravitational universal constant
Our values are given as,
Replacing we have,
Therefore the speed of the object when striking the surface of earth is 4456 m/s
The loudness or sound intensity of the roaring truck engine is inversely proportional to the square of the distance. it follows the law of squares that is
r1^2 / r2^2 = L2/L1
8^2 / 4^2 = L2 / 100 dB
L2 = 400 dB
The answer to this problem is 400 dB increased frim 100 dB.
