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Alex73 [517]
3 years ago
8

The angular momentum about the center of the planet and the total mechanical energy will be conserved regardless of whether the

object moves from small R to large R (like a rocket being launched) or from large R to small R (like a comet approaching the earth).
O True O False
Physics
1 answer:
ValentinkaMS [17]3 years ago
5 0

Answer:

True

Explanation:

The angular momentum around the center of the planet and the total mechanical energy will be preserved irrespective of whether the object moves from large R  to small R. But on the other hand the kinetic energy of the planet will not be conserved because it can change from kinetic energy to potential energy.

Therefore the given statement is True.

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Products must equal which in a chemical reaction?
Evgesh-ka [11]

I think it is reactants

3 0
2 years ago
Can you help me understand force=mass x accleration
gavmur [86]
Force = mass * acceleration

Here is an equation for force, used to calculate force. 

Look at it this way:-

Joules is used to measure force, while mass is measured by kg. Acceleration is measured by m/s/s (meters per second per second, or meters per second squared.)

joules = m/s/s * kg 

Which makes everything fit in just right! :D
6 0
3 years ago
((PLEASE HELP))
Degger [83]

Answer:

Angle of refraction

Explanation:

The incident ray is the ray before it reaches the surface.

The refracted ray is the ray after it reaches the surface.

n₁ is called the index of incidence.

n₂ is called the index of refraction.

θ₁ is called the angle of incidence.

θ₂ is called the angle of refraction.

They are related by Snell's law:

n₁ sin θ₁ = n₂ sin θ₂

5 0
3 years ago
Read 2 more answers
A car is moving with a velocity of45m/s. Is brought to rest in 5s.the distance travelled by car before it comes to rest is
ser-zykov [4K]

Answer:

The car travels the distance of 225m before coming to rest.

Explanation:

v = 45m/s

t = 5s

Therefore,

d = v*t

= 45*5

= 225m

5 0
2 years ago
A block of mass m=1kg sliding along a rough horizontal surface is traveling at a speed v0=2m/s when it strikes a massless spring
topjm [15]

Here we can use the work energy theorem

W_f + W_s = K_f - K_i

here we know that

K_f = 0

as it come to rest finally

K_i = \frac{1}{2}mv_i^2

K_i = \frac{1}{2}\times 1\times 2^2

K_i = 2 J

now work done by friction force will be given as

W_f = - F_f \times d = -\mu mg d

W_f = - \mu(1)(9.8)(0.10) = - 0.98\mu

Work done by spring force is given as

W_s = \frac{1}{2}k(x_i^2 - x_f^2)

W_s = \frac{1}{2}(10)( 0 - 0.10^2)

W_s = -0.05 J

so now plug in all data above

- 0.05 - \mu(0.98) = 0 - 2

\mu = 1.99

so above is the friction coefficient


4 0
3 years ago
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