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SpyIntel [72]
3 years ago
11

What are the main components of the Milky Way?

Physics
1 answer:
Alex787 [66]3 years ago
3 0
The Milky Way<span> has </span>three basic components<span> to its visible matter: the disk (containing the spiral arms), the halo, and the nucleus or central bulge.
(thumbs-up)</span>
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Type your answer...
ArbitrLikvidat [17]

Answer:

50.4÷1.18= 42.7m/s as speed is equal to the distance over the time taken

3 0
3 years ago
These are intense, rotating convectional systems that develop over warm ocean areas in the tropics and subtropics, primarily dur
asambeis [7]

Answer:

True.

Explanation:

During the late summers the SST (sea surface temperature) rises the most which made the wind above the sea moist and warm. Global warming is also one of the cause of the rise in sea surface temperatures. Then the Coriolis effect due to the earth's rotation make these winds to rotate which results in the formation of the cyclones mostly in the areas near to equator.

4 0
3 years ago
A proton of mass 1.67 x 10-27 kg (the charge of a proton is 1.6 x 10-19 C) enters the region between two parallel plates a
Zepler [3.9K]
The answer to the question is 72773
3 0
2 years ago
Which set of atoms will form an ionic compound?
Oksanka [162]

Answer:

The answer is A)

Explanation:

An ionic compound is formed when one atom donates one or more electrons to one or more atoms of another element. Calcium has two valence electrons, which are donated to an atom of oxygen. So, an ionic compound is formed in the reaction involving one calcium atom with an oxygen atom.

8 0
3 years ago
In the Niagara Falls hydroelectric generating plant, the energy of falling water is converted into electricity. The height of th
Charra [1.4K]

Answer:

1960.32306 kg/s

Explanation:

m = Mass of water = 1 kg

g = Acceleration due to gravity = 9.81 m/s²

h = Height from which the water will fall

Potential Energy

PE=mgh\\\Rightarrow PE=1\times 9.81\times 52\\\Rightarrow PE=510.12\ J

One megawatts of power is required

So, flow rate

\dotm=\frac{P}{PE}\\\Rightarrow \dotm=\frac{1\times 10^6}{510.12}\\\Rightarrow \dotm=1960.32306\ kg/s

1960.32306 kg/s is required to produce a megawatt of power

7 0
3 years ago
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