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SpyIntel [72]
3 years ago
11

What are the main components of the Milky Way?

Physics
1 answer:
Alex787 [66]3 years ago
3 0
The Milky Way<span> has </span>three basic components<span> to its visible matter: the disk (containing the spiral arms), the halo, and the nucleus or central bulge.
(thumbs-up)</span>
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Suppose an automobile has 2000 J of kinetic energy. When it moves at twice the speed, what will be its kinetic energy?
Varvara68 [4.7K]

The answer should be 8000 J

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4 years ago
What type of simple machine is an electric fan?
GrogVix [38]

Answer:

An electric fan is considered to be a mixture of several simple machines. It includes the Wheel and Axle type, wedges, and the Inclined plane types. The blades of an electric fan are the inclined planes and the wedges.

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3 years ago
Distance between bholu and golu house house 9 km . bholu has to attend golu birthday party at 7am . he started from his home at
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For the rest 3 km


Bholu need to run in 5 minutes so


He need to 3 × 1000 / 5 × 60 m/s

3000/ 300 = 10 m/s


So , his speed should be 1 m/s to reach in 5 minute



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6 0
4 years ago
Read 2 more answers
The surface of the paper is phosphorescent. When light shines on it, some of the energy is absorbed and re-emitted slowly over t
Ad libitum [116K]

Answer:

No

Explanation:

Recall that the hierarchy of wavelength color from minimum wavelength to maximum wavelength is:

V < I < B < G < Y < O < R; and

E  \ \alpha  \ \dfrac{1}{\lambda}

As a result, blue light has a higher energy level than green and red light.

As a result, the surface glows due to the blue LED. The green LED, on the other hand, would not allow the surface to glow as much as the red LED, which has a lower energy level when compared to the green light. As a result, the red LED would not allow the surface to glow as well.

8 0
3 years ago
At the same instant that a 0.50 kg ball is dropped from 25 m above Earth, a second ball, with a mass of .25 kg, is thrown straig
Anettt [7]

Answer:

A. 7.1m

B. 3.55m/s

C. 1.775m/s^2

Explanation:

First step is to identify given parameters;

Ball 1: m₁ = 0.5kg, u (initial velocity) =0, t = 2seconds

Ball 2: m₂ = 0.25kg, u = 15m/s, t = 2seconds

<u>Second step:</u> we determine the y-coordinate of ball 1 after 2 seconds, using the equation of motion under gravity as shown below;  

y = ut - \frac{gt^2}{2}

y_{1} = 0 X 2 - \frac{9.8 X2^2}{2}

y_{1} = -19.6m

Recall, that the ball was thrown from a height of 25m, total y-coordinate of ball 1 after 2 seconds becomes 25m +(-19.6m)

[tex]y_{1}  = 5.4m[/tex]

<u>Third step</u>: we determine the y-coordinate of ball 2 after 2 seconds

y_{2} = 15 X 2 - \frac{9.8 X2^2}{2}

y_{2} = 10.4m

<u>Fourth step: </u>we determine the y-component of the center mass of the two balls

y = \frac{m_{1}y_{1} +m_{2}y_{2}}{m_{1} +m_{2} }

y = \frac{(0.5)X(5.4) +(0.25) X (10.4)}{(0.5 +0.25) }

y = 7.1m

<u>Fifth step:</u> we solve B part of the question; velocity of the center mass of the two balls

Velocity = \frac{distance of center mass of the two balls (y)}{time}

velocity = \frac{7.1 m}{2 s}

velocity = 3.55m/s

<u>Sixth step:</u> we solve C part of the question; acceleration of the center mass of the two balls

acceleration = \frac{velocity}{time}

acceleration = \frac{3.55}{2}

acceleration = 1.775 m/s^2

7 0
3 years ago
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