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SpyIntel [72]
3 years ago
11

What are the main components of the Milky Way?

Physics
1 answer:
Alex787 [66]3 years ago
3 0
The Milky Way<span> has </span>three basic components<span> to its visible matter: the disk (containing the spiral arms), the halo, and the nucleus or central bulge.
(thumbs-up)</span>
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When four atomic orbitals are mixed to form hybrid orbitals, how many hybrid orbitals are formed?
lilavasa [31]

When four atomic orbitals are mixed to form hybrid orbitals, 4 x sp3 hybrid orbitals are formed.

<span>Carbon's 2s and all three of its 3p </span>orbitals<span> hybridize to form four sp</span>3 orbitals. These orbitals<span> then bond with four hydrogen atoms through sp</span>3-s <span>orbital </span>overlap, creating methane. 

6 0
3 years ago
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Consider a single photon with a wavelength of lambda, a frequency of nu, and an energy of E. What is the wavelength, frequency,
BARSIC [14]

Answer: lambda \lambda, nu \nu, and 100E

Explanation:

The energy E of a photon is given by:

E=h\nu   (1)

Where:

h is the Planck constant

nu is the frequency

On the other hand, we have an expression that relates the frequency of the photn with its wavelength \lambda:

nu=\frac{c}{\lambda} (2) where c is the speed of light

Substituting (2) in (1):

E=h\frac{c}{\lambda}   (3) This is the energy for a single photon

For 100 photons, the energy is:

100E=100(h\frac{c}{\lambda})=100h\nu   (3)

Where the wavelength and the frequency of the light remains constant.

Therefore, the answer is:

\lambda, \nu, and 100E

5 0
3 years ago
A uniform disk of mass 3.25 kg has a radius of 0.100 m and spins with a frequency of 0.550 rev/s. What is its angular momentum?
shutvik [7]

ANSWER:

0.0562 J

STEP-BY-STEP EXPLANATION:

Angular momentum is expressed in terms of moment of inertia and angular velocity. This is expressed as follows:

L=I\cdot\omega

Here, I is the angular momentum and ω is the angular velocity.

Angular momentum is mass time the square of the radius of the object. Moment of inertia for a uniform disk is given as,

I=\frac{1}{2}m\cdot r^2

Here, m is the mass of the disk and r is the radius of the disk.

Replacing:

L=\frac{1}{2}m\cdot r^2\cdot\omega

Convert the units of angular velocity into rad/s.

\begin{gathered} \omega=0.55\text{ rev/s}\cdot\frac{2\pi\text{ rad}}{1\text{ rev}} \\ \omega=3.46\text{ rad/s} \end{gathered}

We replace each data to calculate the angular momentum:

\begin{gathered} L=\frac{1}{2}\cdot3.25\cdot0.1^2\cdot3.46 \\ L=0.0562 \end{gathered}

The angular momentum of the uniform disk is 0.0562 J

7 0
1 year ago
Determine the stopping location of the prize wheel. At this moment it is centered on the number 5. It is spinning with an energy
Maurinko [17]

Answer:

Thanks for the 50 points. Answer eill be always 29.0m

3 0
3 years ago
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Clara's grandfather is a captain of a cargo ship. He prefers to navigate his ship through the moderate neap tides. At these time
spayn [35]

Answer:

The phases are the first and third quarters.

Explanation:

During the first quarter of the moon phases, the line between Earth and the Sun is at a right angle to the line between Earth and the moon. At this time the moon has completed the first quarter of its orbit around the earth. At this point, half of the moon is fully reflecting light from the sun.

Also during the third quarter which is the last quarter, the line between the earth and the sun is at a right angle to the line between the earth and the moon. This is the time when the second half of the moon which was not illuminated during the first quarter becomes completely illuminated.

6 0
3 years ago
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