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SpyIntel [72]
3 years ago
11

What are the main components of the Milky Way?

Physics
1 answer:
Alex787 [66]3 years ago
3 0
The Milky Way<span> has </span>three basic components<span> to its visible matter: the disk (containing the spiral arms), the halo, and the nucleus or central bulge.
(thumbs-up)</span>
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An oxygen atom at a particular site within a DNA molecule can be made to execute simple harmonic motion when illuminated by infr
lukranit [14]

Answer:

The frequency of the sulphur is 2.6×10^13 Hz.

We find the frequency of the sulphur because sulphur is just below the oxygen atom in the periodic table. So, we find it by using the frequency of the oxygen.

Explanation:

As, the frequency in terms of spring constant and mass is :

f = (1/2π) × √(k/m)

k is the spring constant and m is the mass.

Square on both sides of the equation and it becomes then,

f^2 = (1/4π^2) × (k/m)

f^2×m = k/4π^2

Now, we will solve it with oxygen and sulphur because the oxygen atom is chemically replaced with a sulphur atom, the spring constant of the bond is unchanged so, the relation between fo and fs is:

<h3>fo^2×mo = fs^2×ms</h3>

As, fo is the frequency of the oxygen and fs is the frequency of the sulphur atom and mo is the mass of the oxygen and ms is the mass of the sulphur.

So,

fs^2 = (fo^2×mo) / ms

fs = fo×√(mo/ms)

As, we also know the mass of the oxygen and sulphur which is 16amu and 32amu:

fs = (3.7×10^13) × √(16/32)

fs = (3.7×10^13) × 1/√2

fs = 2.6×10^13 Hz.

Therefore, the frequency is: 2.6×10^13 Hz.

4 0
2 years ago
If two cars with the same mass( cars a and b) are moving but one (car b) is moving at twice the speed of car a ?
maria [59]

ANSWER:

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6 0
3 years ago
Which unit abbreviation is a measurement of force?
Rufina [12.5K]
Unit it is c trust please
3 0
2 years ago
Which one of these are considered as mechanical energy?
MA_775_DIABLO [31]

Answer:

Kinetic energy and potential energy.

The term 'mechanical energy' refers to the sum of the kinetic energy and the gravitational potential energy of an object,

8 0
2 years ago
A radio wave transmits 38.5 W/m2 of power per unit area. A flat surface of area A is perpendicular to the direction of propagati
Margaret [11]

Answer:

P=2.57\times 10^{-7}\ N/m^2

Explanation:

Given that,

A radio wave transmits 38.5 W/m² of power per unit area.

A flat surface of area A is perpendicular to the direction of propagation of the wave.

We need to find the radiation pressure on it. It is given by the formula as follows :

P=\dfrac{2I}{c}

Where

c is speed of light

Putting all the values, we get :

P=\dfrac{2\times 38.5}{3\times 10^8}\\\\=2.57\times 10^{-7}\ N/m^2

So, the radiation pressure is 2.57\times 10^{-7}\ N/m^2.

3 0
3 years ago
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