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Naddik [55]
2 years ago
9

Help please, 9th grade math.

Mathematics
2 answers:
PIT_PIT [208]2 years ago
5 0
Sorry I did this in 6th grade, I’ll help tho!

READ THIS, it helps!

24 and 18 (divide each by 3 and you get your 8 and 6)

48 and 36 ( divide both by 6 and you get 8 and 6)

64 and 48 ( you divide 64 by 8 and get 8 and divide 48 by 6 and you get 8)

Answer: Table K
Hope this helps!!
Vikentia [17]2 years ago
4 0

Answer:

table k

Step-by-step explanation:

4:3 ratio

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Rex paid $250 in taxes to the school district that he lives in this year. This year's taxes were a 12% increase from last year.
Verizon [17]

Answer:

$223.21

Step-by-step explanation:

Last year the amount of taxes was x, an unknown amount. That was 100% of last year's tax cost.

This year, taxes went up by 12%, so this year the taxes are 112% of what they were last year. This year the taxes were 112% of x, and they were $250.

112% of x = 250

1.12x = 250

x = 250/1.12

x = 223.21

Answer: $223.21

8 0
2 years ago
3 9/12 + (4 7/12 + 5/12) = 3 9/12 + ____?
Maru [420]

Answer:

5

Step-by-step explanation:

4 7/12 + 5/12 = 4 12/12 which equals 5

8 0
3 years ago
Read 2 more answers
Which relation is not a function?<br><br><br><br><br> Helppppo due now
IRISSAK [1]

Answer:

B.

Step-by-step explanation:

there cannot be two of the same x value's. It would make it a circle on the graph, or something close to that, which isn't a function.

5 0
2 years ago
Find the domain of the function y = 3 tan(23x)
solmaris [256]

Answer:

\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

In other words, the x in f(x) = 3\, \tan(23\, x) could be any real number as long as x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) for all integer k (including negative integers.)

Step-by-step explanation:

The tangent function y = \tan(x) has a real value for real inputs x as long as the input x \ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

Hence, the domain of the original tangent function is \mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

On the other hand, in the function f(x) = 3\, \tan(23\, x), the input to the tangent function is replaced with (23\, x).

The transformed tangent function \tan(23\, x) would have a real value as long as its input (23\, x) ensures that 23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

In other words, \tan(23\, x) would have a real value as long as x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right).

Accordingly, the domain of f(x) = 3\, \tan(23\, x) would be \mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

4 0
2 years ago
119 is what percent of 170
blsea [12.9K]
70 percent of 170 is 119
5 0
3 years ago
Read 2 more answers
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