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2 years ago

Select the statement(s) that describe how climate change ca

Chemistry

1 answer:

Len [333]2 years ago

7 0

Answer:

I think b

Explanation:

I think b becuase I'd it increases it would cause for stuff I dont know i am bot good but a guess is worth a try

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if you take 2.0mL of a 7.0 ppm NaOH solution and dilute it to 250.0mL, calculate the final concentration in ppm.

Oduvanchick [21]

Answer:

C₂ = 0.056 ppm

Explanation:

Given data:

Initial volume = 2.0 mL

Initial concentration = 7.0 ppm

Final volume = 250.0 mL

Final concentration = ?

Solution:

Formula:

C₁V₁ = C₂V₂

C₁ = Initial concentration

V₁ = Initial volume

C₂ = Final concentration

V₂ = Final volume

Now we will put the values in formula.

C₁V₁ = C₂V₂

7.0 ppm × 2.0 mL = C₂ × 250.0 mL

C₂ = 14.0 ppm.mL /250.0 mL

C₂ = 0.056 ppm

4 0

3 years ago

When calcium chloride is dissolved in water, to which end of the adjacent water molecules will a calcium ion be attracted? the o

Lesechka [4]

Ca ionises into Ca^2+. Ca^2+ will be attracted to O^2- ions in the water, since opposite charges attract. (Hydrogen in water forms H^+)

6 0

4 years ago

Can someone help me with this?

Doss [256]

He was involved in the mapping of venus and mars

5 0

4 years ago

A compound is 7.74% hydrogen and 92.26% carbon by mass. At 100°C a 0.6883 g sample of the gas occupies 250 mL when the pressure

ycow [4]

Answer: The molecular formula for the compound is $C_6H_6$

Explanation:

We are given:

Percentage of C = 92.26 %

Percentage of H = 7.74 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 92.26 g

Mass of H = 7.74 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{92.26g}{12g/mole}=7.68moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{7.74g}{1g/mole}=7.74moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 7.68 moles.

For Carbon = $\frac{7.68}{7.68}=1$

For Hydrogen = $\frac{7.74}{7.68}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H = 1 : 1

The empirical formula for the given compound is $CH$

Calculating the molar mass of the compound:

To calculate the molecular mass, we use the equation given by ideal gas equation:

PV = nRT

Or,

$PV=\frac{m}{M}RT$

where,

P = pressure of the gas = 820 torr

V = Volume of gas = 250 mL = 0.250 L (Conversion factor: 1 L = 1000 mL )

m = mass of gas = 0.6883 g

M = Molar mass of gas = ?

R = Gas constant = $62.3637\text{ L. torr }mol^{-1}K^{-1}$

T = temperature of the gas = $100^oC=(100+273)K=373K$

Putting values in above equation, we get:

$820torr\times 0.250L=\frac{0.6883g}{M}\times 62.3637\text{ L torr }mol^{-1}K^{-1}\times 373K\\\\M=\frac{0.6883\times 62.3637\times 373}{820\times 0.250}=78.10g/mol$

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

$n=\frac{\text{Molecular mass}}{\text{Empirical mass}}$

We are given:

Mass of molecular formula = 78.10 g/mol

Mass of empirical formula = 13 g/mol

Putting values in above equation, we get:

$n=\frac{78.10g/mol}{13g/mol}=6$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(1\times 6)}H_{(1\times 6)}=C_6H_6$

Hence, the molecular formula for the compound is $C_6H_6$

8 0

3 years ago

How much heat is necessary to raise the temperature of a 15.0 g metal from 15.0 C to 25.0 C if the specific heat of that metal i

Bumek [7]

The solution would be like this for this specific problem:

E=mcΔT 
= (15 g)(1.91 Jg∘C)(25 ∘C−15 ∘C)
= 28.65 * 10
= 286.5

I hope this helps and if you have any further questions, please don’t hesitate to ask again.

5 0

3 years ago