Answer: 0.25 m/s
Explanation: Speed = wavelengt · frequency
v = λf and frequency is 1/period f = 1/T
Then v = λ/T = 5 m / 20 s = 0.25 m/s
The initial velocity of Ms. Stafford is

, while her acceleration is

This is a uniform accelerated motion, so we can calculate the total distance travelled by Ms. Stafford in a time of

using the law of motion for a uniform accelerated motion:
Answer:
K = 0.076 J
Explanation:
The height of the target, h = 0.860 m
The mass of the steel ball, m = 0.0120 kg
Distance moved, d = 1.50 m
We need to find the kinetic energy (in joules) of the target ball just after it is struck. Let t is the time taken by the ball to reach the ground.

Put all the values,

The velocity of the ball is :

The kinetic energy of the ball is :

So, the required kinetic energy is 0.076 J.
Responder:
192,900.64 Julios
Explicación:
La energía cinética es la energía que posee un cuerpo en virtud de su movimiento. Sea la masa del cuerpo m, su velocidad v.
Energía cinética = 1/2 mv²
Parámetros dados
masa del coche = 500 kg
velocidad = 100 km / h
La velocidad debe estar en m / s según la unidad internacional estándar. Al convertir;
100 km / h = 100 * 1000/3600 m / s
100 km / h = 27,8 m / s
velocidad del cuerpo = 27,8 m / s
Necesario
Energía cinética del coche = 1/2 * 500 * 27,8²
Energía cinética del automóvil = 1/2 * 500 * 771.6
Energía cinética del automóvil = 1/2 * 385,801.28
Energía cinética del automóvil = 192,900.64 Julios
<em>Por lo tanto, la energía cinética del automóvil es 192,900.64 julios.</em>