Answer:
option D - coking or fouling
Explanation:
Coking (not cocking) is the process involving the deposition of small carbon particles (created by simply putting carbon atoms) on a catalyst's accessible surface, leading in a reduction in the area accessible for catalytic activity. This is also sometimes related to fouling catalysts or merely fouling them.
Solid Silicon can be reacted with Nitrogen gas at a high temperature to form silicon nitride (Si3N4).
1.20 moles of Silicon are added to 1.00 moles of Nitrogen gas.
(5 Points) Balance the equation and indicate the phases.
Si (___) + N2 (___) → Si3N4 (___)
(5 Points) What is the limiting reactant? You must show your work.
Answer:
The mass of the element is 141.03701 amu
Explanation:
The catch here is that it notes a " newly found element. " Otherwise you could just refer to the average atomic mass of the element in the periodic table, and receive your solution in a much faster way.
The first isotope has an atomic mass of 139.905 amu, and a respective percent abundance of 37.25%. The second isotope has an atomic mass of 141.709 amu, and the remaining percent abundance, 100% - 37.25% = 62.75% ( given ). We can calculate the mass of the unknown element by associating each percentage with the mass of their respective isotope, over 100%.
Mass = ( ( 139.905 amu )( 37.25% ) + ( 141.709 amu )( 62.75% ) )/ 100,
Mass = ( ( 5211.46125 ) + ( 8892.23975 ) ) / 100,
Mass = ( 14103.701 ) / 100 = 141.03701 amu
Li+(aq) +e- →Li (s) - 3.04
Cl2(g) + 2e- → 2Cl-(aq) +1.36
over all equation
2Li(s) + Cl2(g) →2 Li+(aq) + 2Cl-(aq)
The cell potential of this reaction is + 4.40 V
calculation
Ecell =E cathode - E anode
E cathode is = + 1.36 v
E anode is = - 3.04 V
therefore E cell= 1.36 -(-3.04 ) = 4.40 V
Answer:
6.2 g
Explanation:
1. Calculate the number of half-lives.
2. Calculate the final mass of the substance.