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Sindrei [870]
4 years ago
7

f(x,y)=x^2+y^2-6x-6y+41. How many critical points does g have in R22. If there is a local minimum, what is the value of the disc

riminant D at that point?3. If there is a local maximum, what is the value of the discriminant D at that point?4. If there is a saddle point, what is the value of the discriminant D at that point?5. What is the maximum value of f in R2?6. What is the minimum value of f in R2?

Mathematics
1 answer:
topjm [15]4 years ago
7 0

Answer:

1) There is only a critical point at (3,3).

2) If there is a local minimum, the value of the discriminant must be D>0

3) If there is a local maximum, the value of the discriminant must be D>0

4) If there is a saddle point, the value of the discriminant must be D<0

5) There is not a local maximum of f

6) There is a local minimum at (3,3). f(3,3)=23

Step-by-step explanation:

We have the fuction:

f(x,y)=x^2+y^2-6x-6y+41

Its partial derivatives are:

f_x=2x-6

f_y=2y-6

When f_x=0

0=2x-6 ⇒ 2x=6 ⇒x=3

When f_y=0

0=2y-6 ⇒ 2y=6 ⇒y=3

The critical point is (3,3)

Its second order derivatives are:

f_{xx}=2

f_{yy}=2

f_{xy}=0

The value of the discriminant is

D=f_{xx} \times f_{yy}-(f_{xy})^2=2×2-0=4

As D>0 and f_{xx}>0, there is a local minimun at (3,3)

The value of f(x,y) at (3,3) is:

f(x,y)=x^2+y^2-6x-6y+41=3^2+3^2-6\times3-6\times3+41=9+9-18-18+41=23

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