By dividing the percentage composition with the molar mass of that element we will get the empirical formula. Then using that empirical formula and formula mass we can find the molecular formula.
<u>Explanation:</u>
The chemical properties of any substance are defined obviously by the different types and relative amounts of atoms constituting its primary entities (in case of covalent compounds the primary entities are molecules and ions in the event of ionic compounds).
A percent composition of any compound gives the mass percent of each element present in the compound; in addition to that frequently it is determined experimentally and utilized to derive an empirical formula of any compound. An empirical formula mass of any covalent compound could be comparable with the molar or molecular mass of a compound to acquire a molecular formula.
Answer:
It should be Magnetic fields can push and pull objects without touching
but I only say with touching. Maybe it's an error on you're teachers/Prof behalf.
Answer:
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Answer:
C.) ![K_a = \frac{[H^+][H_2PO_4^-]}{[H_3PO_4]}](https://tex.z-dn.net/?f=K_a%20%3D%20%5Cfrac%7B%5BH%5E%2B%5D%5BH_2PO_4%5E-%5D%7D%7B%5BH_3PO_4%5D%7D)
Explanation:
The general structure for a Ka expression is:
![K_a = \frac{[H^+][A^-]}{[HA]}](https://tex.z-dn.net/?f=K_a%20%3D%20%5Cfrac%7B%5BH%5E%2B%5D%5BA%5E-%5D%7D%7B%5BHA%5D%7D)
In this expression,
-----> Ka = equilibrium constant
-----> [A⁻] = base
-----> [HA] = acid
The products are in the numerator and the reactants are in the denominator. In this case, H₃PO₄ serves as an acid and H₂PO₄⁻ serves as a base.
As such, the equilibrium expression is:
![K_a = \frac{[H^+][H_2PO_4^-]}{[H_3PO_4]}](https://tex.z-dn.net/?f=K_a%20%3D%20%5Cfrac%7B%5BH%5E%2B%5D%5BH_2PO_4%5E-%5D%7D%7B%5BH_3PO_4%5D%7D)