Answer:
A) 8.00 mol NH₃
B) 137 g NH₃
C) 2.30 g H₂
D) 1.53 x 10²⁰ molecules NH₃
Explanation:
Let us consider the balanced equation:
N₂(g) + 3 H₂(g) ⇄ 2 NH₃(g)
Part A
3 moles of H₂ form 2 moles of NH₃. So, for 12.0 moles of H₂:
![12.0molH_{2}.\frac{2molNH_{3}}{3molH_{2}} =8.00molNH_{3}](https://tex.z-dn.net/?f=12.0molH_%7B2%7D.%5Cfrac%7B2molNH_%7B3%7D%7D%7B3molH_%7B2%7D%7D%20%3D8.00molNH_%7B3%7D)
Part B:
1 mole of N₂ forms 2 moles of NH₃. And each mole of NH₃ has a mass of 17.0 g (molar mass). So, for 4.04 moles of N₂:
![4.04molN_{2}.\frac{2molNH_{3}}{1molN_{2}} .\frac{17.0gNH_{3}}{1molNH_{3}} =137gNH_{3}](https://tex.z-dn.net/?f=4.04molN_%7B2%7D.%5Cfrac%7B2molNH_%7B3%7D%7D%7B1molN_%7B2%7D%7D%20.%5Cfrac%7B17.0gNH_%7B3%7D%7D%7B1molNH_%7B3%7D%7D%20%3D137gNH_%7B3%7D)
Part C:
According to the <em>balanced equation</em> 6.00 g of H₂ form 34.0 g of NH₃. So, for 13.02g of NH₃:
![13.02gNH_{3}.\frac{6.00gH_{2}}{34.0gNH_{3}} =2.30gH_{2}](https://tex.z-dn.net/?f=13.02gNH_%7B3%7D.%5Cfrac%7B6.00gH_%7B2%7D%7D%7B34.0gNH_%7B3%7D%7D%20%3D2.30gH_%7B2%7D)
Part D:
6.00 g of H₂ form 2 moles of NH₃. An each mole of NH₃ has 6.02 x 10²³ molecules of NH₃ (Avogadro number). So, for 7.62×10⁻⁴ g of H₂:
![7.62 \times 10^{-4} gH_{2}.\frac{2molNH_{3}}{6.00gH_{2}} .\frac{6.02\times 10^{23}moleculesNH_{3} }{1molNH_{3}}=1.53\times10^{20}moleculesNH_{3}](https://tex.z-dn.net/?f=7.62%20%5Ctimes%2010%5E%7B-4%7D%20gH_%7B2%7D.%5Cfrac%7B2molNH_%7B3%7D%7D%7B6.00gH_%7B2%7D%7D%20.%5Cfrac%7B6.02%5Ctimes%2010%5E%7B23%7DmoleculesNH_%7B3%7D%20%20%7D%7B1molNH_%7B3%7D%7D%3D1.53%5Ctimes10%5E%7B20%7DmoleculesNH_%7B3%7D)
Answer:
A precipitation reaction produces an insoluble solid as a result of the reaction of two dissolved chemicals in a solution. The insoluble solid, called a precipitate, sinks to the bottom of the solution or stays in suspension as cloudy particles.
Explanation: ur welcom
Well I’m. Or to sure but it can’t be B because when you throw the ball the the kinetic energy is still increasing
Answer:
Mg -atomic number 12
electronic configuration -1s² 2s² 2p^6 3s²
Helium is found in the 1st period of the periodic table. It also is part of the noble gases group in the last column (18th) of the table.