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2 years ago

What is force? And tell it's unit

Physics

2 answers:

IRINA_888 [86]2 years ago

3 0

Answer:

force is simply a push or a pull in a particular direction. The unit is N (newton)

Explanation:

hope this helped

Rus_ich [418]2 years ago

3 0

Answer:

In physics force is an influence which changes the motion of an object which has mass

Its unit is N or kgms/2

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A child on a playground swings through a total of 32 degrees. If the displacement is equal on each side of the equilibrium posit

Black_prince [1.1K]

Answer: A = y/cos32

That is the amplitude A in terms of the displacement y.

Explanation: Since the displacement in the question In the question is the same in both direction, it is a Simple Harmonic Motion problem. In s.h.m the amplitude of displacement A is related to the displacement itself y by this simple equation

y = A* cos(theta)

So, A = y/cos(theta)

A = y/cos32.

If the magnitude of the displacement y is given, you just substitute in.

4 0

3 years ago

the coefficient of kinetic friction between a couch and the floor is 0.65. if the couch has a mass of 42 kg and you push it with

Anna [14]

Explanation:

The net force along the horizontal direction is

$\sum{F_x} = F_{applied} - f$

where f is the frictional force. We can find the frictional force by looking at the vertical forces acting on the couch:

$\sum{F_y} = N - mg = 0 \Rightarrow N = mg$

From the definition of frictional force,

$f = \mu{N} = \mu{mg} = (0.65)(42\:\text{kg})(9.8\:\text{m/s}^2)$

$\:\:\:\:= 267.5\:\text{N}$

Therefore, the net force on the couch is

$\sum{F_x} = 600\:\text{N} - 267.5\:\text{kN} = 332.5\:\text{N}$

4 0

2 years ago

A 2.0 kg wood block is launched up a wooden ramp that is inclined at a 30˚ angle. The block’s initial speed is 10 m/s. What vert

WARRIOR [948]

Answer:

The wood block reaches a height of 4.249 meters above its starting point.

Explanation:

The block represents a non-conservative system, since friction between wood block and the ramp is dissipating energy. The final height that block can reach is determined by Principle of Energy Conservation and Work-Energy Theorem. Let suppose that initial height has a value of zero and please notice that maximum height reached by the block is when its speed is zero.

$\frac{1}{2}\cdot m \cdot v^{2} = m \cdot g\cdot h + \mu_{k}\cdot m\cdot g\cdot s \cdot \sin \theta$

$\frac{1}{2}\cdot v^{2} = g\cdot h + \mu_{k}\cdot g\cdot \left(\frac{h}{\sin \theta} \right)\cdot \sin \theta$

$\frac{1}{2}\cdot v^{2} = g\cdot h +\mu_{k}\cdot g\cdot h$

$\frac{1}{2}\cdot v^{2} = (1 +\mu_{k})\cdot g\cdot h$

$h = \frac{v^{2}}{2\cdot (1 + \mu_{k})\cdot g}$ (1)

Where:

$h$ - Maximum height of the wood block, in meters.

$v$ - Initial speed of the block, in meters per second.

$\mu_{k}$ - Kinetic coefficient of friction, no unit.

$g$ - Gravitational acceleration, in meters per square second.

$m$ - Mass, in kilograms.

$s$ - Distance travelled by the wood block along the wooden ramp, in meters.

$\theta$ - Inclination of the wooden ramp, in sexagesimal degrees.

If we know that $v = 10\,\frac{m}{s}$ , $\mu_{k} = 0.20$ and $g = 9.807\,\frac{m}{s^{2}}$ , then the height reached by the block above its starting point is: