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MariettaO [177]
3 years ago
14

A car goes from 0 to 26.8 m/s in 6.2 s. What is the average acceleration of the car?

Physics
1 answer:
Nutka1998 [239]3 years ago
5 0

Answer:

0 - 60 mph = 0 - 26.8 m/s = 0 - 96.6 km/h; 0 - 100 km/h = 0 - 27.8 m/s = 0 - 62.1 mph.

Explanation:

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2. A 2000 kg car with speed 12.0 m/s hits a tree. The tree does not move or
krek1111 [17]

a) The work done by the tree is -1.44\cdot 10^5 J

b) The amount of force applied is 2880 N

Explanation:

a)

According to the work-energy theorem, the work done on the car is equal to the change in kinetic energy of the car. Therefore, we can write:

W=K_f - K_i = \frac{1}{2}mv^2 - \frac{1}{2}mu^2

where

W is the work done on the car

m is the mass of the car

u is its initial speed

v is its final speed

For the car in this problem, we have:

m = 2000 kg

u = 12.0 m/s

v = 0 (since the car comes to a stop, after the crash)

Therefore, the work done by the tree on the car is:

W=0-\frac{1}{2}(2000)(12.0)^2=-1.44\cdot 10^5 J

The work is negative because it is done in the direction opposite to the direction of motion of the car.

b)

The work done by the tree on the car can also be rewritten as

W=Fd

where

F is the force applied on the car

d is the displacement of the car during the collision

In this situation, we have:

W=-1.44\cdot 10^5 J is the work done

d=50.0 cm = 0.50 m is the displacement of the car during the collision

Solving the equation for F, we find the force exerted by the tree on the car:

F=\frac{W}{d}=\frac{-1.44\cdot 10^5 J}{0.50}=-2880 N

Where the negative sign means the force is applied opposite to the direction of motion of the car. Therefore, the magnitude of the force applied is 2880 N.

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

3 0
4 years ago
What is the force required to accelerate a 4 kg rock from 3 m/s to 15 m/s in seconds?
Lera25 [3.4K]

Answer:

16 Newtons

Explanation:

We will use the equation F=ma

First, find the acceleration using the givens.

a=∆v/∆t

a=15-3/3

a=12/3

a=4 m/s^2

Next, plug the acceleration and mass into the equation.

F=ma

F=4kg(4m/s^2)

F=16 Newtons

4 0
4 years ago
A 13.0 g piece of Styrofoam carries a net charge of â5.40 μC and floats above the center of a large horizontal sheet of plastic
kati45 [8]

Answer:

σ =4.180×10^{-9} C/m^2

Explanation:

electric field due to non conducting sheet is

E=\frac{\sigma}{2\epsilon_0}

the force acting on the piece of Styrofoam

Eq= mg

⇒E= mg/q

now,

\frac{mg}{q} = \frac{\sigma}{2\epsilon_0}

⇒\sigma= \frac{2mg\epsilon_0}{q}

\sigma= \frac{2\times0.013\times9.81\times8.85\times10^{-12}}{5.40\times10^{-4}}

charge per unit area (in C/m2) on the plastic sheet σ =4.180×10^{-9} C/m^2

6 0
3 years ago
Where are short distance surface currents located
mylen [45]
<span>https://quizlet.com/11912008/chapter-12-flash-cards/
this sight might help

</span>
7 0
3 years ago
Read 2 more answers
A transverse wave is traveling from right to left. What direction does the medium vibrate?
Elis [28]

the correct answer is C up and down

3 0
4 years ago
Read 2 more answers
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