Answer:
Hello your question is incomplete below is the complete question
Calculate Earths velocity of approach toward the sun when earth in its orbit is at an extremum of the latus rectum through the sun, Take the eccentricity of Earth's orbit to be 1/60 and its Semimajor axis to be 93,000,000
answer : V = 1.624* 10^-5 m/s
Explanation:
First we have to calculate the value of a
a = 93 * 10^6 mile/m * 1609.344 m
= 149.668 * 10^8 m
next we will express the distance between the earth and the sun
--------- (1)
a = 149.668 * 10^8
E (eccentricity ) = ( 1/60 )^2
= 90°
input the given values into equation 1 above
r = 149.626 * 10^9 m
next calculate the Earths velocity of approach towards the sun using this equation
------ (2)
Note :
Rc = 149.626 * 10^9 m
equation 2 becomes
(
therefore : V = 1.624* 10^-5 m/s
4
Just divide 12 by 3, so if it takes 3 seconds, then every second, it goes up 4.
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Answer:
Magnitude of the force is

direction of the force is given as
West of South
Explanation:
As we know that force is a vector quantity and in order to find the resultant of two or more forces we need to add them vectorialy
So here we have

here we know that first force is of magnitude 2 N towards east

second force is also of 2.0 N due North

now from above equation


so magnitude of the force is given as


direction of the force is given as


West of South