Answer:
2) It can be performed in natural settings
Answer:
<h2>hydrogen gas is produced .</h2>
Answer:
Explanation:
we know that 1 km =1000 m and 1 hour =60 min
therefore
239 km/hr =239*1000m/60 min=3983.3 m/min
Answer: The enthalpy of combustion, per mole, of butane is -2657.4 kJ
Explanation:
The balanced chemical reaction is,
The expression for enthalpy change is,
Putting the values we get :
2 moles of butane releases heat = 5314.8 kJ
1 mole of butane release heat = 
Thus enthalpy of combustion per mole of butane is -2657.4 kJ