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galina1969 [7]
3 years ago
12

PH & POH

Chemistry
1 answer:
Mashcka [7]3 years ago
5 0

Answer:

<h2>4.0 </h2>

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ { H}^{+}]

From the question we have

ph =  -  log(9.25 \times  {10}^{ - 5} )  \\  = 4.03385

We have the final answer as

<h3>4.0</h3>

Hope this helps you

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What grade is this? I forgot but if u tell me the grade i can prob remember
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A solar powered car converts __________ energy into _____________ energy.
kotykmax [81]

Answer:

B

Explanation:

Solar power takes in light and turns it into a usable energy. if used in a vehicle that would take light energy and transform it into mechanical energy.

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What is true about the valence shell of the noble gasses?
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The valence shell of noble gases has all 8 valence electrons which means it is full.

Explanation:

8 0
3 years ago
Write a balanced net ionic equation for each of the following aqueous metathesis reactions. Classify each reaction as a neutrali
melamori03 [73]

Answer:

See explanation

Explanation:

A. This is a neutralization reaction.

Molecular equation;

HBr(aq) + CsOH(aq) ---------> CsBr(aq) + H20(l)

Complete ionic equation;

H^+(aq) + Br^-(aq) + Cs^(aq) + OH^-(aq)   --------> Cs^+(aq) + Br^- + H20(l)

Net ionic equation;

H^+(aq) + OH^-(aq)   -------->  H20(l)

B. This is a gas forming reaction;

H2SO4(aq) + Na2CO3(aq) ------->Na2SO4(aq) + H2O(l) + CO2(g)

Complete ionic equation;

2H^+(aq) + SO4^-(aq) + 2Na^+(aq) + CO3^2-(aq)  ------->2Na^+(aq) + SO4^-(aq) + H2O(l) + CO2(g)

Net ionic equation;

2H^+(aq) + CO3^2-(aq)  -------> + H2O(l) + CO2(g)

C. This a precipitation reaction

Molecular equation;

CdCl2(aq) + Na2S(aq) ------->CdS(s) + 2NaCl(aq)

Complete ionic equation;

Cd^2+(aq) + 2Cl^-(aq) + 2Na^+(aq) + S^2-(aq) ---------> CdS(s) + 2Na^+(aq) +  2Cl^-(aq)

Net ionic equation;

Cd^2+(aq) +  S^2-(aq) ---------> CdS(s)

8 0
3 years ago
What is the speed of an electron that has a de Broglie wavelength of 100. nm?
Advocard [28]

<u>Answer:</u> The speed of the electron is 7.24\times 10^3m/s

<u>Explanation:</u>

To calculate the speed of electron for given wavelength, we use the equation given by De-Broglie's, which is:

\lambda=\frac{h}{mv}

where,

\lambda = De-Broglie's wavelength = 100nm=100\times 10^{-9}m

h = Planck's constant = 6.6\times 10^{-34}Js

m = mass of the electron = 9.11\times 10^{-31}kg

v = speed of the electron = ?

Putting values in above equation, we get:

100\times 10^{-9}m=\frac{6.6\times 10^{-34}Js}{9.11\times 10^{-31}kg\times v}\\\\v=\frac{6.6\times 10^{-34}Js}{9.11\times 10^{-31}kg\times 100\times 10^{-9}m}=7.24\times 10^3m/s

Hence, the speed of the electron is 7.24\times 10^3m/s

4 0
3 years ago
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