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galina1969 [7]
3 years ago
12

PH & POH

Chemistry
1 answer:
Mashcka [7]3 years ago
5 0

Answer:

<h2>4.0 </h2>

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ { H}^{+}]

From the question we have

ph =  -  log(9.25 \times  {10}^{ - 5} )  \\  = 4.03385

We have the final answer as

<h3>4.0</h3>

Hope this helps you

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describe characteristics of different climate zones as they relate to latitude,elevation,and proximity to bodies of water. (scie
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7 0
3 years ago
In acetyl CoA formation, the carbon-containing compound from glycolysis is oxidized to produce acetyl CoA. From the following co
kondor19780726 [428]

Answer:

- Net Input: NAD⁺, coenzyme A, pyruvate

- Net Output: NADH, acetyl CoA, CO₂

- Not input or output: O₂, ADP, glucose and ATP

Explanation:

Hello,

In this case, it is important to recall that acetyl-CoA is produced either by oxidative decarboxylation of pyruvate derived from glycolysis, which is carried out into the mitochondrial matrix, by cause of the oxidation of high-order fatty acids, or by oxidative degradation of very specific amino acids. Acetyl-CoA then enters in the citric acid cycle where it is oxidized in the light of energy production.

In this manner, during such processes, there are some net inputs and outputs, therefore, they are sorted as show below, considering there some of them not classified neither as input nor output:

- Net Input: NAD⁺, coenzyme A, pyruvate

- Net Output: NADH, acetyl CoA, CO₂

- Not input or output: O₂, ADP, glucose and ATP

Best regards.

8 0
4 years ago
Which scientist would best describe the motion of the earth?
Burka [1]
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5 0
3 years ago
The Prandtl number, Pr, is a dimensionless group important in heat transfer. It is defined as Pr - Cp*mu/k where Cp is the heat
algol [13]

Answer:

The Prandtl number for this example is 14,553.

Explanation:

The Prandlt number is defined as:

Pr=\frac{C_{p}*\mu}{k}

To compute the Prandlt number for this case, is best if we use the same units in every term of the formula.

\mu=1896 \frac{lbm}{ft*h}*\frac{1000 g}{2.205 lbm}*\frac{3.281 ft}{1 m}*\frac{1h}{3600s}  =7938 \frac{g}{m*s}

Now that we have coherent units, we can calculate Pr

Pr=\frac{C_{p}*\mu}{k}=0.66*7938/0.36=14553

8 0
3 years ago
[07.03] what is the ph of a 6.40 × 10-3 m solution of sodium hydroxide, naoh?
Katena32 [7]
POH = - log [OH] 
<span>pOH = - log (6.40 × 10-3) </span>
<span>pOH = 2.19 </span>

<span>pH + pOH = 14 </span>

<span>pH = 14 - pOH </span>
<span>pH = 14 - 2.19 </span>
<span>pH = 11.8</span>
6 0
4 years ago
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