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saw5 [17]
3 years ago
11

An example of suspended particulate matter is:-

Chemistry
1 answer:
uysha [10]3 years ago
7 0
It is option A- unburnt carbon
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Someone can help me please??
kramer

C to D

Explanation:

it rises faster between those two points

4 0
3 years ago
Read 2 more answers
Q.1 What is one joule work ? ​
Irina-Kira [14]

Answer:

See below.

Explanation:

It is equal to the energy transferred to (or work done on) an object when a force of one newton acts on that object in the direction of the force's.

Best Regards!

8 0
3 years ago
Read 2 more answers
When one carbon atom combines with 2 oxygen atoms the resulting substance is called what
Aloiza [94]
CO2 contains one atom of carbon and two atoms of oxygen.
The molecule is called Carbon dioxide, indicating that it is covalent and that there are two oxygen present. 
8 0
3 years ago
If the hydrogen ion concentration, [H+], in a solution is 4.59 x 10-6 M, what is [OH-]?
atroni [7]

Answer:

2.18x10^-9 M

Explanation:

From the question given,

Hydrogen ion concentration, [H+] = 4.59x10^-6 M

Hydroxide ion, [OH-] =?

The hydroxide ion concentration, [OH-] in the solution can be obtained as follow:

[H+] x [OH-] = 1x10^-14

4.59x10^-6 x [OH-] = 1x10^-14

Divide both side by 4.59x10^-6

[OH-] = 1x10^-14 / 4.59x10^-6

[OH-] = 2.18x10^-9 M

6 0
3 years ago
What is the concentration of a potassium iodate solution after you complete the following porcedure? Pipette 10 mL of a 0.31 M p
zubka84 [21]

<u>Given:</u>

Initial concentration of potassium iodate (KIO3) M1 = 0.31 M

Initial volume of KIO3 (stock solution) V1 = 10 ml

Final volume of KIO3 V2 = 100 ml

<u>To determine:</u>

The final concentration of KIO3 i.e. M2

<u>Explanation:</u>

Use the relation-

M1V1 = M2V2

M2 = M1V1/V2 = 0.31 M * 10 ml/100 ml = 0.031 M

Ans: The concentration of KIO3 after dilution is 0.031 M

4 0
3 years ago
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