Because as the air hits the charcoal it becomes ash and changes color.
Answer:
The mass percentage of bromine in the original compound is 81,12%
Explanation:
<u>Step 1: Calculate moles AgBr</u>
moles AgBr = mass AgBr / molar mass AgBr
= 0.8878 g / 187.77 g/mol
= 0.00472812 moles AgBr
⇒
Since 1 mol AgBr contains 1 mol Br-
Then the amount of moles Br- in the original sample must also have been 0.00472812 moles
<u>Step 2:</u> Calculating mass Br-
mass Br- = molar mass Br x moles Br-
= 79.904 g/mol x 0.00472812 mol
= 0.377796 g Br-
⇒
There were 0.377796 g Br- in the original sample
<u>Step 3:</u> Calculating mass percentage Br-
⇒mass percentage = actual mass Br- / total mass x 100%
% mass Br = 0.377796 g / 0.4657 g x 100 %
= 81.12%
<span>(3) C4H8</span>
C=12, H=1
CH2= 12+2=14
(CH2)n=56g/mol
14n=56
n=4
(CH2)4=C4H8
Answer:
The given metal is beryllium.
Explanation:
Given data:
Mass of metal = 74 g
Volume of metal = 40 cm³
Which metal is this = ?
Solution:
First of all we will calculate the density.
it is mass divided by volume.
d = m/v
d = 74 g/40 cm³
d = 1.85 g/cm³
In literature it is given that the density of beryllium is 1.85 g/cm³. Thus given metal is beryllium.
Answer:
4H2O(g)+3Fe(s)⟶Fe3O4(s)+4H2(g)
4H2O(g)+3Fe(s)⟶Fe3O4(s)+4H2(g)
Is there a question?
Explanation:
