The distance travelled by the ball that is thrown horizontally from a window that is 15.4 meters high at a speed of 3.01 m/s is 5.34 m
s = ut + 1 / 2 at²
s = Distance
u = Initial velocity
t = Time
a = Acceleration
Vertically,
s = 15.4 m
u = 0
a = 9.8 m / s²
15.4 = 0 + ( 1 / 2 * 9.8 * t² )
t² = 3.14
t = 1.77 s
Horizontally,
u = 3.01 m / s
a = 0 ( Since there is no external force )
s = ( 3.01 * 1.77 ) + 0
s = 5.34 m
Therefore, the distance travelled by the ball before hitting the ground is 5.34 m
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In a way it’s true because you can get a ticket for getting caught littering
Sum the vector components:
Dx = 225* Cos(180)+ 78*Cos(225)= -280.154 km
Dy = 225* Sin(180)+ 78*Sin(225) = -55.154 km
displacement:
Sqrt(Dx^2+Dy^2) = 285.532 km
Arctan(Dy/Dx) = 191.137degrees CCW
OR:
11.137 degrees South of West
