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gayaneshka [121]
2 years ago
14

If 4.23 mol of ethane (C2H6) undergo combustion according to the unbalanced equation

Chemistry
1 answer:
juin [17]2 years ago
7 0

Answer:

T$4U

Explanation:

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What is the molarity of a solution of 58.7 grams of MgCl2 in 359 ml of solution?
jekas [21]

Answer:

1.72 M

Explanation:

Molarity is the molar concentration of a solution. It can be calculated using the formula a follows:

Molarity = number of moles (n? ÷ volume (V)

According to the information provided in this question, the solution has 58.7 grams of MgCl2 in 359 ml of solution.

Using mole = mass/molar mass

Molar mass of MgCl2 = 24 + 35.5(2)

= 24 + 71

= 95g/mol

mole = 58.7g ÷ 95g/mol

mole = 0.618mol

Volume of solution = 359ml = 359/1000 = 0.359L

Molarity = 0.618mol ÷ 0.359L

Molarity = 1.72 M

6 0
3 years ago
Which ion is the only negative ion produced by an Arrhenius base in water?
Snowcat [4.5K]
According to Arrhenius Theory of acids and bases, an Arrhenius base, when dissolving in water, produces the only negative ion: OH-. 

Therefore, (3) OH- is the correct answer.

Hope this is helpful~
6 0
3 years ago
Which statement is true for one molecule of sulfur trioxide?A.(There are three atoms of sulfur and one atom of oxygen.B.(There a
ki77a [65]
The answer would be D. This is because sulfur is on it's own, meaning one. while tri is a prefix for three so there are three oxygen atoms.
5 0
3 years ago
Read 2 more answers
Select the letter of a category on which you should focus when proofreading.
oee [108]
B. Who, what, when, where, why, and how. Those are the most important and key componants in a story.
8 0
3 years ago
Two systems with heat capacities 19.9 J mol-1 K-1 and 28.2 ] mol 1 K-1 respectively interact thermally and come to an equilibriu
MAVERICK [17]

Answer : The initial temperature of system 2 is, 19.415^oC

Explanation :

In this problem we assumed that the total energy of the combined systems remains constant.

-q_1=q_2

m\times c_1\times (T_f-T_1)=-m\times c_2\times (T_f-T_2)

The mass remains same.

where,

C_1 = heat capacity of system 1 = 19.9 J/mole.K

C_2 = heat capacity of system 2 = 28.2 J/mole.K

T_f = final temperature of system = 30^oC=273+30=303K

T_1 = initial temperature of system 1 = 45^oC=273+45=318K

T_2 = initial temperature of system 2 = ?

Now put all the given values in the above formula, we get

-19.9J/mole.K\times (303-318)K=28.2J/mole.K\times (303-T_2)K

T_2=292.415K

T_2=292.415-273=19.415^oC

Therefore, the initial temperature of system 2 is, 19.415^oC

8 0
3 years ago
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