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schepotkina [342]
3 years ago
15

Imagine that there is a small rocky body caught by Earth’s gravity. Draw a comic-strip cartoon

Physics
1 answer:
vladimir1956 [14]3 years ago
6 0

To create this comic strip you can use a narration describing each step and illustrate each one with one image or drawing.

Creating a comic strip involves using images and short texts to explain a specific idea or phenomenon. In the case of the process for a meteor to enter Earth you can use the following ideas.

  • A meteoroid approaches the Earth at high speed and draw a meteor traveling near to different planets and approaching Earth.
  • What is that? and draw the Earth wondering who or what is approaching.
  • The meteoroid enters the atmosphere of the Earth and becomes a meteor and draw the rocky body burning
  • The rocky body crashes with the surface becoming a meteorite and draw the zone where the meteorite crashed.

Learn more about comic in: brainly.com/question/1418309

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Un cuerpo de 480 g de masa es atraído con una fuerza de 3.9 E-6 N por otro cuerpo de 196 g de masa. Calcula la distancia a la qu
Soloha48 [4]

Answer:

La distancia entre los dos cuerpos es aproximadamente 1.269 milímetros.

Explanation:

Asumamos que ambos cuerpos son partículas, la fuerza de atracción (F), en newtons, entre ambos cuerpos se define mediante la Ley de Newton de la Gravitación Universal, cuya ecuación es:

F = G \cdot \frac{m_{1}\cdot m_{2}}{r^{2}} (1)

Donde:

G - Constante de la gravitación universal, en metros cúbicos por kilogramo-segundo cuadrado.

m_{1}, m_{2} - Masas de los cuerpos, en kilogramos.

r - Distancia entre los cuerpos, en metros.

Si sabemos que G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}, m_{1} = 0.48\,kg, m_{2} = 0.196\,kg y F = 3.9\times 10^{-6}\,N, entonces la distancia entre los dos cuerpos es:

r = \sqrt{\frac{G\cdot m_{1}\cdot m_{2}}{F} }

r \approx 1.269\times 10^{-3}\,m

Es decir, la distancia entre los dos cuerpos es aproximadamente 1.269 milímetros.

5 0
3 years ago
Write down the role played by four digestive juices in digestion and the
valentinak56 [21]

Answer:

Digestive juices secreted by various organs such as salivary glands in the mouth, stomach, liver and pancreas help in the process of digestion of food. Saliva secreted by the salivary glands in the mouth aids in the breakdown of starch present in the food to simple sugar

Explanation:

3 0
3 years ago
What helps determine how easily magma flows?
natta225 [31]
<span>the amount of silica in the magma</span>
3 0
3 years ago
Ali is training for a marathon he knows he can run 12 miles in 114 minutes if he keeps this pace how long will it take him to ru
tigry1 [53]

Answer:

249.5 minutes

Explanation:

Ali's speed is given by:

v=\frac{d}{t}

where

d is the distance covered

t is the time taken

We know that he can run d = 12 mi in t = 114 min, so he can keep a speed of

v=\frac{12 mi}{114 min}=0.105 mi/min

The length of a maraton is

L = 26.2 miles

So we can find the time it takes for Ali to complete the marathon as follows

t = \frac{L}{v}=\frac{26.2 mi}{0.105 mi/min}=249.5 min

5 0
3 years ago
A thin soap bubble of index of refraction 1.33 is viewed with light of wavelength 550.0nm and appears very bright. Predict a pos
faust18 [17]

Answer:

The possible thickness of the soap bubble = 1.034\times 10^{-7}\ m.

Explanation:

<u>Given:</u>

  • Refractive index of the soap bubble, \mu=1.33.
  • Wavelength of the light taken, \lambda = 550.0\ nm = 550.0\times 10^{-9}\ m.

Let the thickness of the soap bubble be t.

It is given that the soap bubble appears very bright, it means, there is a constructive interference takes place.

For the constructive interference of light through a thin film ( soap bubble), the condition of constructive interference is given as:

2\mu t=\left ( m+\dfrac 12 \right )\lambda.

where m is the order of constructive interference.

Since the soap bubble is appearing very bright, the order should be 0, as 0^{th} order interference has maximum intensity.

Thus,

2\mu t=\left (0+\dfrac 12\right )\lambda\\t=\dfrac{\lambda}{4\mu}\\\ \ = \dfrac{550\times 10^{-9}}{4\times 1.33}\\\ \ = 1.034\times 10^{-7}\ m.

It is the possible thickness of the soap bubble.

6 0
3 years ago
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