Answer:
1)
2)
3)
4)
Explanation:
1)
We can use the following equation:

Here, the initial velocity in the y-direction is zero, the final y position is zero and the initial y position is 25 m.


2)
The equation of the motion in the x-direction is:



3)
The velocity in the y-direction of the stone will be:



Now, the velocity in the x-direction is 15 m/s then the velocity will be:

4)
The angle of this velocity is:
Then α=55.92° negative from the x-direction.
I hope it helps you!
Detailed Explanation:
1) Rusting of Iron
4Fe + 3O2 + 2H2O -> 2Fe2O32H2O
Reactants :-
Fe = 4
O = 3 * 2 + 2 = 8
H = 2 * 2 = 4
Products :-
Fe = 2 * 2 = 4
O = 2 * 3 + 2 = 8
H = 2 * 2 = 4
2) Fermentation of sucrose…
C12H22O11 + H2O -> 4C2H5OH + 4CO2
Reactants :-
C = 12
H = 22 + 2 = 24
O = 11 + 1 = 12
Products :-
C = 4 * 2 + 4 = 12
H = 4 * 5 + 4 = 24
O = 4 * 2 + 4 = 12
Looking closely at the way I have taken the total number of elements on the reactants and products side, you can solve the rest.
All the Best!
The environmental impact of mining affects, nesting habitats for wildlife. Wildlife either moves on, or dies.
hope this helps:)
Answer:

Explanation:
Given that

From the diagram

By differentiating with time t

When x= 10 m

θ = 64.53°
Now by putting the value in equation



Therefore rate of change in the angle is 0.038\ rad/s
B. Gabriella is slowing down at the same rate that Kendall is speeding up, and Franklin is not accelerating.