Find the value of the expression

Write this equation in vertex form. y = x^2 -12x +20

kotegsom [21]

Answer:

$y = (x-6) ^ 2 -16$

Step-by-step explanation:

The vertex form for a quadratic equation has the following form:

$y = (x-h) ^ 2 + k$

Where the vertice of the equation is the point (h, k)

To transform the equation $y = x ^ 2 -12x +20$ in its vertex forms we must find its vertex.

Be a quadratic equation of the form:

$ax ^ 2 + bx + c$

Where a, b and c are real numbers, then the vertex of the equation will be:

$x = - \frac{b}{2a}$

For the given equation:

$b = -12\\a = 1$

Therefore the vertice is:

$x = - \frac{-12}{2(1)}\\\\x = 6$

Now we substitute x = 6 into the equation and find the value of k.

$y = (6) ^ 2 -12 (6) +20\\\\y = -16 = k$

Therefore the vertice is: (6, -16)

And the equation is:

$y = (x-6) ^ 2 -16$

8 0

2 years ago

Read 2 more answers

Which multiplication problem is equivalent to 338÷34?

gtnhenbr [62]

Answer:

What are the options?

Step-by-step explanation:

7 0

2 years ago

True or false? A correct answer is worth (2 pts). Explain how you know for the additional (2 pts). Using complete sentence for (

PtichkaEL [24]

answer (in words)

FALSE. the coordinate pair (5, 2) is not a solution to the equation $2x+3y=10$ . in order to figure out whether or not the statement is true or false, plug the $x$ and $y$ values from the coordinate pair (5, 2) into the given equation, $2x+3y=10$ . if both sides of the equation end up equal, the coordinate pair is a solution to the equation. if not, the coordinate pair is not a solution to that equation.

(i hope i explained that well enough, i'm better at explaining it algebraically as opposed to putting it into words lol)

answer (algebraic/steps for solving)

first, plug in 5 for $x$ in the equation $2x+3y=10$ .

$2x+3y=10$ ⇒ $2(5)+3y=10$

then plug in 2 for $y$ .

$2(5)+3y=10$ ⇒ $2(5)+3(2)=10$

now your equation is $2(5)+3(2)=10$ . all that's left to do is to simplify. you can do this in whatever order you'd like, but i'll start with multiplying 2 · 5.

$2(5)+3(2)=10$ ⇒ $10 + 3(2) = 10$

multiply 3 · 2.

$10 + 3(2) = 10$ ⇒ $10 + 6 = 10$

add 10 + 6.

$10 + 6 = 10$ ⇒ $16=10$

16 and 10 are not equal, therefore (5, 2) is not a solution to the equation $2x+3y=10$ . in order for a coordinate pair to be the solution to an equation, both sides of the equation need to end up equal after solving and simplifying.

i hope this helps! have a great rest of your day <3

6 0

2 years ago

Every prime number greater than 10 has a digit in the ones place that is include in wich set of numbers A- 1,3,7,9 B-1,3,5,9 D-1

marta [7]

That's very interesting. I had never thought about it before.
Let's look through all of the ten possible digits in that place,
and see what we can tell:

-- 0:
   A number greater than 10 with a 0 in the units place is a multiple of
   either 5 or 10, so it's not a prime number.

-- 1:
    A number greater than 10 with a 1 in the units place could be
    a prime (11, 31 etc.) but it doesn't have to be (21, 51).

-- 2:
   A number greater than 10 with a 2 in the units place has 2 as a factor
   (it's an even number), so it's not a prime number.

-- 3:
   A number greater than 10 with a 3 in the units place could be
   a prime (13, 23 etc.) but it doesn't have to be (33, 63) .

-- 4:
   A number greater than 10 with a 4 in the units place is an even
   number, and has 2 as a factor, so it's not a prime number.

-- 5:
   A number greater than 10 with a 5 in the units place is a multiple
   of either 5 or 10, so it's not a prime number.

-- 6:
   A number greater than 10 with a 6 in the units place is an even
   number, and has 2 as a factor, so it's not a prime number.

-- 7:
   A number greater than 10 with a 7 in the units place could be
   a prime (17, 37 etc.) but it doesn't have to be (27, 57) .

-- 8:
   A number greater than 10 with a 8 in the units place is an even
   number, and has 2 as a factor, so it's not a prime number.

-- 9:
   A number greater than 10 with a 9 in the units place could be
   a prime (19, 29 etc.) but it doesn't have to be (39, 69) .

So a number greater than 10 that IS a prime number COULD have
any of the digits 1, 3, 7, or 9 in its units place.

It CAN't have a 0, 2, 4, 5, 6, or 8 .

The only choice that includes all of the possibilities is 'A' .

4 0

2 years ago

A customer service phone line claims that the wait times before a call is answered by a service representative is less than 3.3

Vika [28.1K]

Answer:

(A) Yes, since the test statistic is in the rejection region defined by the critical value, reject the null. The claim is the alternative, so the claim is supported.

Step-by-step explanation:

Null hypothesis: The wait time before a call is answered by a service representative is 3.3 minutes.

Alternate hypothesis: The wait time before a call is answered by a service representative is less than 3.3 minutes.

Test statistic (t) = (sample mean - population mean) ÷ sd/√n

sample mean = 3.24 minutes

population mean = 3.3 minutes

sd = 0.4 minutes

n = 62

degree of freedom = n - 1 = 62 - 1 = 71

significance level = 0.08

t = (3.24 - 3.3) ÷ 0.4/√62 = -0.06 ÷ 005 = -1.2

The test is a one-tailed test. The critical value corresponding to 61 degrees of freedom and 0.08 significance level is 1.654

Conclusion:

Reject the null hypothesis because the test statistic -1.2 is in the rejection region of the critical value 1.654. The claim is contained in the alternative hypothesis, so it is supported.

5 0

2 years ago