The scuba diver's position relative to sea level after the 4.6 minutes is 5.1 ft.
Given:
A scuba diver descends in the water at a rate of 23 1/2 feet per minute for 2.6 minutes.
A scuba diver ascends at a rate of 28 feet per minute for 2 minutes after seeing a big fish.
To find :
The scuba diver's position relative to sea level after the 4.6 minutes.
Solution:
Rate of a scuba diver descending in the water for 2.6 minutes = 

Distance covered by a scuba diver in 2.6 minutes = 

Rate of a scuba diver ascending for 2 minutes = 

Distance covered by a scuba diver in 2 minutes = 

The position of scuba diver after 4.6 minutes relative to sea level:

The scuba diver's position relative to sea level after the 4.6 minutes is 5.1ft.
Learn more about ascending rate and descending rate here:
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Answer:

Step-by-step explanation:
-2g=?

Answer:
let x=rate of the rowing team in still water
x+4=rate of the rowing team with current
x-4=rate of the rowing team against current
travel time=distance/rate
..
90%2F%28x%2B4%29=10%2F%28x-4%29
90x-360=10x+40
80x=400
x=5 rate of the rowing team in still water=5 mph
Well, first off 1 hr =60 minutes. 60 min - 45 min = 15 minutes extra. what is one hour before 4:15? 3:15! Add the subtracted 15 minutes to get 3:30... Hope this helps