3 years ago

Suppose you increase your walking speed from 6 m/s to 14 m/s in a period of 3 s. What is the acceleration?

Physics

1 answer:

Doss [256]3 years ago

5 0

Acceleration = (14-6)/3 = 2.667m/s²

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abruzzese [7]

Answer:

$\boxed{\sf Kinetic \ energy \ (KE) = 85 \ J}$

Given:

Mass (m) = 6.8 kg

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To Find:

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Explanation:

Formula:

$\boxed{ \bold{\sf KE = \frac{1}{2} m {v}^{2} }}$

Substituting values of m & v in the equation:

$\sf \implies KE = \frac{1}{2} \times 6.8 \times {5}^{2}$

$\sf \implies KE = \frac{1}{ \cancel{2}} \times \cancel{2} \times 3.4 \times 25$

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