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seraphim [82]
3 years ago
6

Help me ultra sound vs infrasound

Physics
1 answer:
hodyreva [135]3 years ago
4 0

Answer:

ultrasound: high pitch, above the human range of hearing, reflects back

infrasound: longitudinal waves, in the human range, low pitch

Explanation:

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A pillow with mass of 0.3 kg sits on a bed with a coefficient of static friction of 0.6. What is the maximum force of static fri
lys-0071 [83]
The maximum force of static friction is the product of normal force (P) and the coefficient of static friction (c). In a flat surface, normal force is equal to the weight (W) of the body. 
 
                        P = W = mass x acceleration due to gravity
    
                    P = (0.3 kg) x (9.8 m/s²) = 2.94 kg m/s² = 2.94 N

Solving for the static friction force (F), 
                                              F = P x c 
 
                                      F = (2.94 N) x 0.6 = 1.794 N

Therefore, the maximum force of static friction is 1.794 N. 



5 0
3 years ago
Read 2 more answers
Please Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
arsen [322]

Answer:

Given that

speed u=4*10^6 m/s

electric field E=4*10^3 N/c

distance b/w the plates d=2 cm

basing on the concept of the electrostatices

now we find the acceleration b/w the plates  to find the horizontal distance traveled by the electron when it hits the plate.

acceleration a=qE/m=1.6*10^{-19}*4*10^3/9.1*10^{-31} =0.7*10^{15}=7*10^{14} m/s

now we find the horizontal distance traveled by electrons hit the plates

horizontal distance

X=u[2y/a]^{1/2}

=4*10^6[2*2*10^{-2}/7*10^{14}]^{1/2}

=3*10^{-2}= 3 cm

5 0
3 years ago
HELP!
Goryan [66]

Answer:

The solved problem is in the photo. Hope it helps.

3 0
3 years ago
A certain 48 V electric forklift can lift up to 7000 lb at a
Gwar [14]

Answer:

256.25 A

Explanation:

7 0
2 years ago
Consider the free-body diagram. If you want the box to move, the force applied while dragging must be greater than the
VLD [36.1K]

You would want it to be greater than D. friction force

It needs be greater than the friction applied to it.

6 0
3 years ago
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