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Marianna [84]
2 years ago
10

In ΔSTU, u = 280 inches, ∠T=63° and ∠U=29°. Find the length of t, to the nearest 10th of an inch.

Mathematics
1 answer:
Galina-37 [17]2 years ago
8 0

Answer:

t = 514.6in.

Step-by-step explanation:

280/sin(29°) = t/sin(63°)

t = 280*sin(63°)/sin(29°)

t = 514.6 in. (to the nearest 10th of an inch)

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During a sale at the bookstore​, books sold for ​$4 and magazines sold for ​$3.50. Jan spent ​$22 and bought a total of 6 books
Vinvika [58]

Answer:

four magazines and two books

Step-by-step explanation:

3.50*4= 14

4*2= 8

14+8= 22

8 0
2 years ago
Help me with these problems (show work) thanks ❤️❤️
yanalaym [24]

Answer:

#1. 12x9x5+= 426

#2. 6x14.8= 784.14

#3. 6x6x8x8= 143.11

Step-by-step explanation:

Hoped that helped!

6 0
2 years ago
(High points) please solve with explanation
AysviL [449]

Answer:

The area and the perimeter of the picture are:

  • <u>Area = 160 cm^2</u>
  • <u>Perimeter = 67.31 cm</u>

Step-by-step explanation:

To find the area of that figure, you can find the area how if it was a rectangle and next subtract the area of the triangle in the upper part. The area of a rectangle could be found by the next formula:

  • Area of a rectangle = base * height

As you can see in the picture, the base is 16 cm and the height is 12 cm, then we replace in the formula:

  • Area of a rectangle = 16 cm * 12 cm
  • Area of a rectangle = 192 cm^2

Now, we calculate the area of the triangle to subtract to the area we found and obtain the real area, the formula to obtain the area of a triangle is:

  • Area of a triangle = (base * height) / 2

The height of the triangle is 8 cm, and the base is 8 cm too, because you subtract to the base of the rectangle (16 cm) the measurements in the upper part (16 - 4 - 4 = 8), Now, we replace in the formula:

  • Area of a triangle = (8 cm * 8 cm) / 2
  • Area of a triangle = (64 cm^2) / 2
  • Area of a triangle = 32 cm^2

We subtract to the found area:

  • Area of the picture = 192 cm^2 - 32 cm^2
  • <u>Area of the picture = 160 cm^2</u>

To find the perimeter, you must add all the sides of the picture, but, as you can see, there is a side that doesn't have the measurent, this is the hypotenuse of the triangle used before, but how we know the other sides, we can use Pythagorean theorem:

  • a^{2}+b^{2}=c^{2}

Where:

  • a = Opposite leg (8 cm)
  • b = Adjacent leg (8 cm)

So, we replace in the theorem:

  • a^{2}+b^{2}=c^{2}
  • (8 cm)^{2}+(8cm)^{2}=c^{2} (and we clear c)
  • \sqrt{(8 cm)^{2}+(8cm)^{2}} =c
  • \sqrt{64 cm^{2}+64cm^{2}} =c
  • \sqrt{128cm^{2}} =c
  • c = 11.3137085 cm
  • c ≅ 11.31 cm

At last, we add all the sides of the picture begining by the base and going by the left side:

  • Perimeter of the picture = 16 cm + 12 cm + 4 cm + 11.31 cm + 8 cm + 4 cm + 12 cm
  • <u>Perimeter of the picture = 67.31 cm approximately</u>.
7 0
3 years ago
Needing help to find the inequality
tiny-mole [99]

http://goblues.org/faculty/grantm/files/2015/12/Practice-Test-3.7-Solutions.pdf

I think it's question number three. Sorry if the link dosen't work.

4 0
3 years ago
You invest an initial $1,000 in an account that has an annual interest rate of 2%, compounded quarterly. how much money will you
kiruha [24]
Check the attached file for the answer.

8 0
3 years ago
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