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GrogVix [38]
2 years ago
9

Plss help me asap!!!!​

Chemistry
1 answer:
Reptile [31]2 years ago
7 0

Answer:

answer is in picture

Explanation:

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7. List all of the variables that you controlled or kept the same.<br>Salt water​
satela [25.4K]

Answer:

Temperature is a common type of controlled variable. If a temperature is held constant during an experiment, it is controlled. Other examples of controlled variables could be an amount of light, using the same type of glassware, constant humidity, or duration of an experiment.

Explanation:

3 0
3 years ago
Plants are responsibe for a very important energy transformation what answer
Soloha48 [4]

Plants are chlorophyll-containing photosynthetic organisms. Thus, they convert solar or radiant energy into chemical energy under the process termed as photosynthesis.

<u>Explanation:</u>

  • Plants are chlorophyll-containing photosynthetic living beings. Consequently, they convert radiant energy into chemical energy under the procedure named  photosynthesis.  
  • Except for remote ocean hydro-thermal environment, the sun is the only source for all biological systems on earth. Plants catch just 2-10 percent of the solar radiation and transmit it as chemical energy. All creatures are reliant for their nourishment on producers (plants), either directly or indirectly. So there is a stream of energy from the sun (radiant energy) to producers and then to consumers (chemical energy).

5 0
2 years ago
How many moles are there in 35.2g of Gold?
ki77a [65]

Explanation:

196.96655

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5 0
3 years ago
How many molecules are there in 0.75 mol NH3
vitfil [10]
3 *0.75 = 2.25 mol that’s is ur answer for this question
4 0
2 years ago
What is the ph of a solution of 0.400 m k2hpo4, potassium hydrogen phosphate?
dusya [7]
When we can get Pka for K2HPO4 =6.86 so we can determine the Ka :

when Pka = - ㏒ Ka

          6.86 = -㏒ Ka 

∴Ka = 1.38 x 10^-7

by using ICE table:

               H2PO4- →  H+  + HPO4
initial      0.4 m            0         0

change     -X                +X       +X

Equ       (0.4-X)               X          X

when Ka = [H+][HPO4] / [H2PO4-]

by substitution:

1.38 X 10^-7 = X^2 / (0.4-X)   by solving for X

∴X = 2.3x 10^-4 

∴[H+] = X = 2.3 x 10^-4

∴PH = -㏒[H+]

        = -㏒ (2.3 x 10^-4)
 ∴PH  =  3.6

3 0
3 years ago
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