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nekit [7.7K]
3 years ago
14

Calculate the atomic mass of bromine. The two isotopes of bromine have atomic masses and relative abundance of 78.2 (50.69%) AMU

and 80.92 AMU (49.31%)
Chemistry
1 answer:
UNO [17]3 years ago
8 0
So let's say the first bromine isotope is Br-1 and the second one is Br-2.

For Br-1 and Br-2 we will have to divide the percentage by 100.
So Br-1 will go from 50.69% to 0.5069.
And Br-2 will go from 49.31 to 0.4931.

For Br-1 you need to multiply abundance of 78.2 and 0.5069 which equals 39.63958.
And then multiply 80.92 and 0.4931 for Br-2, which then equals 39.901652.

Now you add the totals you got which are 39.63958 + 39.901652 and that equals 79.541232, which is the total atomic mass
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I need to know how to do number 1. If you can please show the work so I can try to understand it. Thanks!!
Elodia [21]
Here's how you would solve it. The process should be the same for the others.

8 0
3 years ago
What volume of solution must be added to 4.0 mol of NaCl to make a 1.2 M solution?
Aleksandr [31]

Answer:

\boxed {\boxed {\sf 3.3 \ liters}}}

Explanation:

Molarity is a measure of concentration in moles per liter.

molarity=\frac{moles \ of \ solute}{liters \ of \ solution}}

The solution has a molarity of 1.2 M or 1.2 moles per liter. There are 4.0 moles of NaCl, the solute. We don't know the liters of solution, so we can use x.

  • molarity= 1.2 mol/L
  • moles of solute= 4.0 mol
  • liters of solution =x

Substitute the values into the formula.

1.2 \ mol/L = \frac{4.0 \ mol}{x}

Since we are solving for x, we must isolate the variable. Begin by cross multiply (multiply the 1st numerator and 2nd denominator, then the 1st denominator and 2nd numerator.

\frac {1.2 \ mol/L}{1}=\frac{ 4.0 \ mol}{x}

4.0 \ mol *1=1.2 \ mol/L *x

4.0 \ mol = 1.2 \ mol/L *x

x is being multiplied by 1.2 moles per liter. The inverse of multiplication is division, so divide both sides by 1.2 mol/L

\frac{4.0 \ mol}{1.2 \ mol/L} = \frac{1.2 \ mol/L *x}{1.2 \ mol/L}

\frac{4.0 \ mol}{1.2 \ mol/L}=x

The units of moles (mol) will cancel.

\frac{4.0 }{1.2 } \ L =x

3.33333333 \ L=x

The original measurements both have 2 significant figures, so our answer must have the same. For the number we found, this is the tenths place.

The 3 in the hundredth place tells us to leave the 3 in the tenths place.

3.3 \ L\approx x

Approximately  <u>3.3 liters of solution</u> are needed to make a 1.2 M solution with 4.0 moles of sodium chloride.

7 0
3 years ago
How do you do part B?
galina1969 [7]
I cannot see the whole equation.Therefore I shall not answer

7 0
3 years ago
while doing an experiment you got stuck and didn't know how to proceed what will you do to continue with the experiment​
stiv31 [10]

Answer:

Look for extra things to do, small details, until you find a big enough one to go off that to continue

Explanation:

n/a

7 0
3 years ago
Refer to the example about diatomic gases A and B in the text to do problems 19 - 27. How many grams in 3 moles of A2?
dedylja [7]

B.) 3

hope you have a okay day

(GAME OF THRONES RULES

7 0
3 years ago
Read 2 more answers
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