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Jlenok [28]
2 years ago
12

If an atom has 6 valence electrons, how many electrons does it need to gain to achieve a stable electron configuration?

Chemistry
2 answers:
jek_recluse [69]2 years ago
7 0

Answer:

2 electrons does it need to gain to achieve a stable electron configuration

Explanation:

Valance electron:

The electrons which are present in the outer most energy level are known as valance electron. This can be calculated by the group number of the element. Generally the group number is same as the valance electrons of any elements.

Octet rule: Generally all atoms will lose, gain or share electrons to attain 8 valence electrons; the electron configuration of the nearest noble element.

If an atom has 6 valence electrons; to get stable electron configuration of the nearest noble element require 2 electrons.

2 electrons does it need to gain to achieve a stable electron configuration

shusha [124]2 years ago
4 0

it would need to gain 2 more for it to achieve a stable configuration

the best way to remember this is the noble gasses all have 8 valence electrons and that they are the most stable elements on the periodic table

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How many atoms of phosphorus are in 4.5 grams of tetraphosphorus decoxide?
Alexxx [7]

Answer:

In 4.5 grams of tetraphosphorus decoxide we have 3.85 * 10^22  phosphorus atoms

Explanation:

Step 1: Data given

tetraphosphorus decoxide = P4O10

Molar mass of P4O10 = 283.89 g/mol

Mass of P4O10 = 4.5 grams

Number of Avogadro = 6.022 * 10^23 / mol

Step 2: Calculate moles of P4O10

Moles P4O10 = mass P4O10 / molar mass P4O10

Moles P4O10 = 4.5 grams / 283.89 g/mol

Moles = 0.016 moles

Step 3: Calculate moles of P

For 1 mol P4O10 we have 4 moles of phosphorus

For 0.016 moles P4O10 we have 4*0.016 = 0.064 moles P

Step 4: Calculate number of P atoms

Number of P atoms = moles P * number of Avogadro

Number of P atoms = 0.064 moles * 6.022*10^23

Number of P atoms = 3.85 * 10^22 atoms

In 4.5 grams of tetraphosphorus decoxide we have 3.85 * 10^22  phosphorus atoms

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Calculate the volume of dry co2 produced at body temperature (37 ∘c) and 0.970 atm when 25.5 g of glucose is consumed in this re
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I believe the balanced chemical equation is:

C6H12O6 (aq) + 6O2(g) ------> 6CO2(g) + 6H2O(l) 

 

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moles CO2 = 0.8493 mol

 

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<span>V = nRT  / P</span>

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<span>V = 22.28 L</span>

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