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creativ13 [48]
3 years ago
6

The test to detect the presence of a certain protein is 98% accurate for corn plants that have the protein and 97% accurate for

corn plants that
do not have the protein.
If 3.5% of the corn plants in a given population actually have the protein, the probability that a randomly chosen plant is detected incorrectly is
Mathematics
1 answer:
larisa [96]3 years ago
3 0

Using the given percentages, it is found that the probability that a randomly chosen plant is detected incorrectly is 0.02965 = 2.965%.

<h3>Percentages:</h3>

The percentages associated with an incorrect detection are:

  • 2% of 3.5%(have the protein).
  • 3% of 96.5%(do not have the protein).

Hence:

p = 0.02(0.035) + 0.03(0.965) = 0.02965

The probability that a randomly chosen plant is detected incorrectly is 0.02965 = 2.965%.

You can learn more about percentages and probabilities at brainly.com/question/25960993

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3 years ago
Cubic yards of concrete will be required for 14 parking lot light pole standards
riadik2000 [5.3K]

Using conversion of units and volume of a cylinder, it is found that 23.17 cubic yards of concrete are needed, option D.

The volume of a cylinder of radius r and height h is given by:

V = \pi r^2h

In this problem:

  • We want the volume in cubic yards, thus, the units of radius and height have to be in yards.
  • 32 inches in diameter, thus 16 inches of radius. Since each inch has 0.0278 yards, this is a radius of 0.44 yards, thus r = 0.44.
  • Height of 8 feet, and since each feet has 0.33 yards, this is a height of 2.67 yards, thus h = 2.67
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Then:

V = 14\pi(0.44)^2(2.67) = 23.17

23.17 cubic yards of concrete are needed, option D.

A similar problem is given at brainly.com/question/22789697

3 0
3 years ago
Calculate the value of the sample variance. Round your answer to one decimal place. 9_5,9_5,2,9_5
Ugo [173]

Answer:

s^2 = 0.01

Step-by-step explanation:

Given

Values: 9/5, 9/5, 2, 9/5

Required

Calculate the sample variance

Sample variance is calculated using:

s^2 = \frac{\sum (x_i - \overline x)^2}{n - 1}

First, we calculate the mean

\overline x = \frac{\sum x}{n}

\overline x = \frac{9/5 + 9/5 + 2 + 9/5}{4}

\overline x = \frac{7.4}{4}

\overline x = 1.85

s^2 = \frac{\sum (x_i - \overline x)^2}{n - 1} becomes

s^2 = \frac{(9/5 - 1.85)^2+(9/5 - 1.85)^2+(2 - 1.85)^2+(9/5 - 1.85)^2}{4 - 1}

s^2 = \frac{(-0.05)^2+(-0.05)^2+(0.15)^2+(-0.05)^2}{4 - 1}

s^2 = \frac{0.0025+0.0025+0.0225+0.0025}{3}

s^2 = \frac{0.03}{3}

s^2 = 0.01

<em>Hence, the variance is 0.01</em>

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