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Kitty [74]
3 years ago
6

What percent of 111 is 94?

Mathematics
1 answer:
konstantin123 [22]3 years ago
3 0

Answer:

I’d say 84.68%

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A target with a diameter of 14cm has 4 scoring zones by concentric circles. The diameter of the center circle is 2 cm. The width
Leni [432]

Answer:

48.98\%

Step-by-step explanation:

we know that

The probability that it will hit a point in the outer (yellow) ring is equal to divide the area of the yellow ring by the total area of the target

step 1

Find the area of the yellow ring

A=\pi [7^{2} -5^{2}]

A=24\pi\ cm^{2}

step 2

Find the total area of the target

A=\pi [7^{2}]

A=49\pi\ cm^{2}

step 3

Find the probability

24\pi/49\pi=0.4898

Convert to percentage

0.4898*100=48.98\%

4 0
3 years ago
Read 2 more answers
Please help
OlgaM077 [116]
First, we're going to see the candies per minute that machine C packs.
150 / 2 = 75

Now that we know that machine C packs 75 candies per minute, we're going to multiply the candies machine C makes by 11 minutes.
75 x 11 = 825

We're now gonna do the same with machine D.
130 x 11 = 1430

Then we're going to find the difference between machine C and machine D, we do this because the question basically asks how much more candies can machine D pack than machine C.
1430 - 825 = 605 candies.

This is how we find our final answer.

Our answer would be D) 605.

Hope this helps!~
4 0
3 years ago
Somebody please help it would be much appreciated.
Sav [38]

Answer:

25

Step-by-step explanation:

as you can see test a is further away from the ruler you have to put it at 0 so that you can get your answer I am not sure if it's correct or not

7 0
3 years ago
Read 2 more answers
Find the projection of u onto v<br> URGENT HELP
padilas [110]

Given:

Two vectors are:

u=\left

v=\left

To find:

The projection of u onto v.

Solution:

Magnitude of a vector v=\left is:

|v|=\sqrt{a^2+b^2}

Dot product of two vector v_1=\left and v_2=\left is:

v_1\cdot v_2=a_1a_2+b_1b_2

Formula for projection of u onto v is:

Proj_vu=\dfrac{u\cdot v}{|v|^2}v

Proj_vu=\dfrac{\left \cdot \left }{(\sqrt{2^2+17^2)^2}}\left

Proj_vu=\dfrac{0\cdot 2+6\cdot 17}{4+289}\left

Proj_vu=\dfrac{0+102}{293}\left

On further simplification, we get

Proj_vu=\dfrac{102}{293}\left

Proj_vu=\left

Proj_vu=\left

Therefore, the projection of u onto v is Proj_vu=\left.

3 0
3 years ago
please help me if you can if your going to say I'm cheating i don't care cause i know I'm not thanks!!​
Dovator [93]
Big fat badussy balls
4 0
3 years ago
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