I believe it is E because Cesium has the most electrons, protons, and neutrons.
Answer:
f = 1.87 × 10¹⁹ s⁻¹
Explanation:
Given data:
Wavelength of light = 1.6 ×10⁻¹¹ m
Frequency of light = ?
Solution:
Formula:
speed of light = wavelength × frequency
Frequency = speed of light / wavelength
speed of light = 3× 10⁸ m/s
Now we will put the values in formula:
Frequency = speed of light / wavelength
f = 3× 10⁸ m/s / 1.6 ×10⁻¹¹ m
f = 1.87 × 10¹⁹ s⁻¹
Answer:
it will explode (not intensely) there is some oxygen in the bottle so the cap would pop off violently, the longer it stays in the fire the more energy is being pent up.
Explanation:
Answer:
Yes
Explanation:
Denatured ethanol fuel is a polar solvent, which is soluble in water. A
Polar solvent is a compound with a charge separation in chemical bonds, such as alcohol, most acids, or ammonia. These have affinity with water and will dissolve easily. Denatured fuel ethanol has a flash point of -5 ° F and a vapor density of 1.5, indicating that it is heavier than air.
Consequently, ethanol vapors do not rise, similar to the gasoline vapors they are looking for lower altitudes. The specific gravity of denatured fuel ethanol is 0.79, which indicates that it is lighter than water and has a self-ignition temperature of 709 ° F and a boiling point of 165-175 ° F. Like gasoline, the most denatured fuel, the greatest danger of ethanol as an engine fuel component is its flammability.
It has a wider flammable range than gasoline (LEL is 3% and UEL is 19%).
Answer:
40.5% is abundance of X-122
Explanation:
we know there are two naturally occurring isotopes of X, X-120 and X-122.
First of all we will set the fraction for both isotopes
X for the isotopes having mass 122
1-x for isotopes having mass 12
0
The average atomic mass of X is 120.81 amu
we will use the following equation,
122x + 120 (1-x) = 120.81
122x + 120 - 120x = 120.81
122x- 120x = 120.81 -120
2x = 0.81
x= 0.81/2
x= 0.405
0.405 × 100 = 40.5%
40.5% is abundance of X-122 because we solve the fraction x.
now we will calculate the abundance of X-120.
(1-x)
1 - 0.405 = 0.595
0.595 × 100 = 59.5 %
59.5 % for X-120.