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Pani-rosa [81]
2 years ago
12

Need help on this question asap pleasee

Physics
1 answer:
shepuryov [24]2 years ago
8 0

Answer:

My aunt died and I am felling down today

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(TCO-8) A band-pass filter has fC1 = 5 kHz and fC2 = 88 kHz. Calculate Bandwidth (BW) and center frequency (fo) for this filter.
Temka [501]

Bandwidth is the difference between the upper and lower frequencies in a continuous band of frequencies.

Mathematically can be expressed as,

BW = F_{c2}-F_{c1}

The upper frequency is 88Hz and the lower frequency is 6, therefore the Bandwidth would be,

BW = (88-5)kHz

BW = 83kHz

The center frequency is given on the basis of the square root of the multiplication of the two reference frequencies, then,

f_0 = \sqrt{f_{c1}*f_{c2}}

f_0 = \sqrt{88*5}

f_0 = 20.97kHz

7 0
3 years ago
Bone has a Young's modulus of about
Oksanka [162]

Answer:

505.62 mm

Explanation:

Young's modulus of a material is given by,

Y=\frac{Stress}{Strain}

Stress is the force experienced by the material per unit area (which is why stress has the same units as pressure).

Strain is the ratio between the change in length/area/volume to the original length/area/volume of the material (and hence a dimensionless quantity). Basically, it gives us a measure of the change in dimensions due to the stress experienced.

So, for the given problem,

Y=\frac{Stress}{\Delta L/L}

or, 1.8\times100=\frac{1.59\times108}{\Delta L/0.53}      (since we need to find the compression of the bone at the critical stress point)

or, \Delta L=\frac{1.59\times108\times0.53}{1.8\times100} m=0.50562m=505.62mm

8 0
3 years ago
A 25.0 kg block is initially at rest on a horizontal surface. A horizontal force of 75.0 N is required to set the block in motio
QveST [7]

Answer:

(a) 0.31

(b) 0.245

Explanation:

(a)

F' = μ'mg.................... Equation 1

Where F' = Horizontal Force required to set the block in motion, μ' = coefficient of static friction, m = mass of the block, g = acceleration due to gravity.

make μ' the subject of the equation above

μ' = F'/mg............. Equation 2

Given: F' = 75 N, m = 25 kg

constant: g = 9.8 m/s²

Substitute these values into equation 2

μ' = 75/(25×9.8)

μ' = 75/245

μ' = 0.31.

(b) Similarly,

F = μmg.................. Equation 3

Where F = Horizontal force that is required to keep the block moving with constant speed, μ = coefficient of kinetic friction.

make μ the subject of the equation

μ = F/mg.............. Equation 4

Given: F = 60 N, m = 25 kg, g = 9.8 m/s²

Substitute these values into equation 4

μ  = 60/(25×9.8)

μ = 60/245

μ = 0.245

3 0
3 years ago
A car slams on its brakes, producing friction between the tires and the road. Into which type of energy is the mechanical energy
lawyer [7]

mechanical energy of the car converted to HEAT. (Don't touch ! and watch for smoke !)

6 0
3 years ago
Which of these is NOT an example of a reference direction?
Aleonysh [2.5K]
Down because it doesn’t state a direction
7 0
3 years ago
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