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Pani-rosa [81]
2 years ago
12

Need help on this question asap pleasee

Physics
1 answer:
shepuryov [24]2 years ago
8 0

Answer:

My aunt died and I am felling down today

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An old truck compresses a spring scale at the junkyard by 25 cm. The spring constant for the industrial scale at the junkyard is
vichka [17]
Using F = Ke
F = 39200×(25÷100) = 39200×0.25
F= 9800N
8 0
4 years ago
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if a Firebird travels at a velocity of 0 to 60 mph in four seconds traveling east what was the acceleration of the Firebird
Tresset [83]

Answer:

6.7 m/s^2

Explanation:

The formula of acceleration is:

\displaystyle{\vec{a} = \dfrac{\Delta \vec{v}}{\Delta t} = \dfrac{v_2 - v_1}{t_2-t_1}}

where \displaystyle{\vec{a}} is acceleration, \displaystyle{\vec{v}} is velocity and \displaystyle{t} is time. \displaystyle{v_2} means final velocity. \displaystyle{v_1} means initial velocity, \displaystyle{t_2} means final time and \displaystyle{t_1} means initial time.

We are given that the Firebird travels at velocity of 0 to 60 mph in four seconds. Therefore:

  • Our initial velocity starts at 0 mph.
  • Our final velocity is at 60 mph.
  • Our initial time is 0 second.
  • Our final time is 4 seconds.

Since it travels to the east then our vector will be positive. However, acceleration has to be in m/s^2 unit (Sl unit) so we'll have to convert from mph (miles per hours) to m/s (meters per second) first.

We know that:

  • A mile equals to 1609.344 meters.
  • An hour equals to 60 minutes which a minute equals to 60 seconds. So 60 minutes will equal to 3600 seconds.

Now we divide 1609.344 by 3600 to find a unit rate of m/s:

\displaystyle{\dfrac{1609.344}{3600} \ \, \sf{m/s}}\\\\\displaystyle{= 0.44704 \ \, \sf{m/s}}

Now multiply 0.44704 m/s by 0 and 60 to get velocity in m/s unit:

  • Initial velocity = 0 m/s
  • Final velocity = 60 * 0.44704 = 26.82 m/s

Time is already in second so no need for conversion. Substitute known information in the formula:

\displaystyle{\vec{a} = \dfrac{26.82-0}{4-0}}\\\\\displaystyle{\vec{a} = \dfrac{26.82}{4}}\\\\\displaystyle{\vec{a} = 6.7 \ \, \sf{m/s^2}}

Therefore, the Firebird will accelerate at the rate of 6.7 m/s^2.

3 0
2 years ago
Can anyone help me with questions a and c​
Ganezh [65]

Answer:

a)

n=sin i/sin r

n= -0.305/-0.428

n=0.713

b)

sin c=1/n

sin c=1/0.713

sin c= 1.403

c=sin⁻¹(1.403)

c= 40.842°

Explanation:

i hope it will be helpful

plzzz mark as brainliest

5 0
3 years ago
The lifting and removal of loose material by wind is called _____.
Mumz [18]
It would be gravity i do beileve

7 0
4 years ago
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How can a simple machine lift a heavy load with smaller effort​
solniwko [45]

Answer:

The axle is fixed to a frame or a block. The pulley is normally fixed to a support above the load. The load is tied to one end of the rope and the effort is applied at the other end. Such a pulley makes our work easier by simply changing the direction of the force, i.e. a load is lifted up using a downward effort.

May be this will help U

6 0
3 years ago
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