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2 years ago

Solve for x and graph the solution on the number line below.

Mathematics

2 answers:

Goshia [24]2 years ago

8 0

Answer:

x ≥ 4

Step-by-step explanation:

Multiply to remove the fraction, then set equal to 0 and solve.

Inequality Form:

x ≥ 4

Interval Notation:

[ 4 , ∞ ]

The graph will be a horizontal line.

Komok [63]2 years ago

7 0

Answer:

See image

Step-by-step explanation:

"Solve for x" means get the x all by itself. So multiply by -2 on both sides of the inequality. When you multiply by a negative number like that ***!!!*** its VERY important that you reverse the inequality symbol in the math sentence.

x/-2 <= -2

(-2) x/-2 <= -2 (-2)

x >= 4

This sentence can now be graphed on a number line. It says 'all the numbers bigger than four or equal to four' See image for graph.

Since there is an equal to bar under the greater (less) than symbol. You use a closed dot (sometimes higher level math classes want you to use a square bracket instead [ The closed dot or square bracket means the four is included in the answer. The arrow goes to the right, because those are all the numbers bigger than four.

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Which statement is true about the equation? 3y-6x=-3

Mekhanik [1.2K]

B.When x=-4, y=-9 and when x=2, y=3.

3y-6x=-3
3(-9) - 6(-4)= -3
-27 +24 =-3
-3 = -3


3y-6x=-3
3(3) -6 (2) = -3
9 - 12 = -3
-3 = -3

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2 years ago

What is the product? (4y - 3) (2y^2 +3y - 5)

igomit [66]

(4y-3)(2y²+3y-5)

First , let's start with "4y"

4y*2y² = 8y³

4y*3y = 12y²

4y*-5 = -20y

Next, let's multiply by "-3"

-3*2y² = -6y²

-3*3y = -9y

-3*-5 = 15

Now, let's combine all of our values.

8y³+12y²-6y²-20y-9y+15 = 8y³+6y²-29y+15

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2 years ago

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vlada-n [284]

number of full boxes is 2

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2 years ago

Read 2 more answers

Highlight three ordered pairs that will form a relation with a range of {-3, 4, 7}.

sdas [7]

Answer:

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Step-by-step explanation:

8e xhjdndd dd

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2 years ago

Solve the following System of Three Equations: x−3y+z=−15 2x+y−z=−2 x+y+2z=1

SashulF [63]

Answer:

x = -3 , y = 4 , z = 0

Step-by-step explanation:

Solve the following system:

{x - 3 y + z = -15

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Choose an equation and a variable to solve for.

In the first equation, look to solve for z:

{x - 3 y + z = -15

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Solve for z.

Subtract x - 3 y from both sides:

{z = 3 y + (-x - 15)

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Perform a substitution.

Substitute z = -15 - x + 3 y into the second and third equations:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

x + y + 2 (-15 - x + 3 y) = 1

Hint: | Expand the left hand side of the equation x + y + 2 (-15 - x + 3 y) = 1.

x + y + 2 (-15 - x + 3 y) = x + y + (-30 - 2 x + 6 y) = -30 - x + 7 y:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

-30 - x + 7 y = 1

Hint: | Choose an equation and a variable to solve for.

In the second equation, look to solve for x:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

-30 - x + 7 y = 1

Hint: | Isolate terms with x to the left hand side.

Subtract 15 - 2 y from both sides:

{z = -15 - x + 3 y

3 x = 2 y - 17

-30 - x + 7 y = 1

Hint: | Solve for x.

Divide both sides by 3:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

-30 - x + 7 y = 1

Hint: | Perform a substitution.

Substitute x = (2 y)/3 - 17/3 into the third equation:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 - 73/3 = 1

Hint: | Choose an equation and a variable to solve for.

In the third equation, look to solve for y:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 - 73/3 = 1

Hint: | Isolate terms with y to the left hand side.

Add 73/3 to both sides:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 = 76/3

Hint: | Solve for y.

Multiply both sides by 3/19:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

y = 4

Hint: | Perform a back substitution.

Substitute y = 4 into the first and second equations:

{z = -x - 3

x = -3

y = 4

Hint: | Perform a back substitution.

Substitute x = -3 into the first equation:

{z = 0

x = -3

y = 4

Hint: | Sort results.

Collect results in alphabetical order:

Answer: {x = -3 , y = 4 , z = 0

4 0

2 years ago