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snow_tiger [21]
3 years ago
15

Sample Question : A Digital Ohmmeter is being use to measure a component. The meter indicates 3.725K ohms. This indicates​

Physics
1 answer:
Marysya12 [62]3 years ago
5 0

The Digital Ohmmeter indicates 3,725 Ohms.

<u>Given the following data:</u>

  • Resistance = 3.725K ohms.

A Digital Ohmmeter is an electronic device that is designed and developed for the measurement of resistance in an electric circuit. Also, the standard unit of resistance is Ohms.

<u>Note:</u> K is equal to 1000.

Therefore, we would multiply the value of the resistance measured with Digital Ohmmeter by 1000:

Resistance = 3.275 \times 1000

Resistance = 3,725 Ohms.

Read more on Digital Ohmmeter here: brainly.com/question/82784

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Which is NOT something that all green plants have in common?
Anvisha [2.4K]

Answer:

Number 4

Explanation:

7 0
3 years ago
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To travel at a constant speed,a car engine provides 24 KW of useful powers. The driving force on the car is 600N.AT what speed d
Whitepunk [10]

Answer: D. 40

Explanation:

Power = Force * Velocity

Force = 600N

Power needs to be converted to Watts:

= 24 * 1,000

= 24,000 W

24,000 = 600 * Velocity

Velocity = 24,000/600

= 40 m/s

3 0
3 years ago
Imagine that you fill a balloon at sea level (1.0 atm) with 18 L of air. You are taking the balloon to Denver, Colorado, for a b
Salsk061 [2.6K]

Answer:

21.18 L

Explanation:

From the question given above, the following data were obtained:

Initial pressure (P₁) = 1 atm

Initial volume (V₁) = 18 L

Final pressure (P₂) = 0.85 atm

Final Volume (V₂) =?

With the application of the Boyle's law equation, we can obtain the final volume (i.e the new volume) of the gas as follow:

P₁V₁ = P₂V₂

1 × 18 = 0.85 × V₂

18 = 0.85 × V₂

Divide both side by 0.85

V₂ = 18 / 0.85

V₂ = 21.18 L

Therefore, the new volume of the gas will be 21.18 L

8 0
3 years ago
Two cats are sitting on a 30 m hill. One cat
V125BC [204]

Answer:

Cat with 6 kg sitting on a 30 meter hill has greater potential energy.

Explanation:

gravitational potential energy (J) = mass (kg) × gravitational field × height (m)

<h3 /><h3><u>Note</u>:</h3>

gravitational field in Earth is 10 N/kg = <u>fixed unit</u>

<h3 /><h3><u>Given</u>:</h3>

1st Cat: 4 kg

2nd Cat: 6 kg

Both of their height is 30 meters.

<h3><u>Solve for g.p.e</u>:</h3>

1st cat = mgh = 4 × 10 × 30 = 1200 Joules

2nd cat = mgh = 6 × 10 × 30 = 1800 Joules

3 0
2 years ago
Two particles with charges of 2nC and 5nC are separated by a distance of 3m. The charge 2nC is placed on the left. Find the forc
Vanyuwa [196]

Answer:

1\cdot 10^{-8} N to the left

Explanation:

The magnitude of the electrostatic force between two charges is given by the following equation:

F=k\frac{q_1 q_2}{r^2}

where:

k=9\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the magnitude of the two charges

r is the distance between the two charges

Moreover, the force is:

- Attractive if the charges have opposite sign

- Repulsive if the charges have same sign

In this problem, we have:

q_1=2nC=2\cdot 10^{-9}C is the magnitude of charge 1

q_2=5nC =5\cdot 10^{-9}C is the magnitude of charge 2

r = 3 m is the distance between the two charges

Substituting, we find the force on both charges:

F=\frac{(9\cdot 10^9)(5\cdot 10^{-9})(2\cdot 10^{-9}}{3^2}=1\cdot 10^{-8} N

Here, the two charges are both positive, so the force is repulsive; since the 2 nC charge is on the left, this means that the force on this charge is to the left (away from the 5 nC charge).

5 0
3 years ago
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