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Len [333]
3 years ago
10

To travel at a constant speed,a car engine provides 24 KW of useful powers. The driving force on the car is 600N.AT what speed d

oes it travel? A 2.5 B 4.0 C.25 D 40
Physics
1 answer:
Whitepunk [10]3 years ago
3 0

Answer: D. 40

Explanation:

Power = Force * Velocity

Force = 600N

Power needs to be converted to Watts:

= 24 * 1,000

= 24,000 W

24,000 = 600 * Velocity

Velocity = 24,000/600

= 40 m/s

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1) Little Timmy wants to measure how tall his house is. He doesn’t have a tape measure but does have a stopwatch. He recruits Bi
kifflom [539]

1) 13.7 m

The motion of the rock is a free fall, with constant acceleration g=9.8 m/s^2 towards the ground, so the total distance it covers is given by the SUVAT equation:

S=\frac{1}{2}gt^2

where S is the height of the house, and t is the time the rock takes to reach the ground. Substituting t=1.67 s, we find:

S=\frac{1}{2}(9.8 m/s^2)(1.67 s)^2=13.7 m

2) 105.5 m

The motion of the stuffed chicken is a projectile motion, with a uniform horizontal motion (with constant velocity of v=36.0 m/s) and a vertical accelerated motion (with constant acceleration of g=9.8 m/s^2).

First of all, we can find the total time of the ball by considering the vertical motion only. We know the vertical distance covered, S=42.2 m, so the time of the fall is

S=\frac{1}{2}gt^2\\t=\sqrt{\frac{2S}{g}}=\sqrt{\frac{2(42.2 m)}{9.8 m/s^2}}=2.93 s

And now we can consider the horizontal motion to find the horizontal distance covered by the stuffed chicken:

d=vt=(36.0 m/s)(2.93 s)=105.5 m

3) 49.4 m

Again, the motion of the ball is a projectile motion, with a horizontal motion and a vertical motion.

The range of a projectile launched from the ground can be found by using the formula:

d=\frac{v^2}{g} sin 2 \theta

where, in this case:

v = 22.0 m/s is the initial velocity

\theta=45^{\circ}

Substituting into the formula, we find

d=\frac{(22.0 m/s)^2}{9.8 m/s^2}(sin (2\cdot 45^{\circ}))=49.4 m

4) 9.6 m/s^2

The frictional force acting on the monkey is given by:

F_f = \mu mg=(0.16)(31.0 kg)(9.8 m/s^2)=48.6 N

where \mu is the coefficient of friction and m is the mass of the monkey.

We have two forces acting on the monkey: the push of F=345 N and the frictional force acting in the opposite direction. According to Newton's second law, the net force will be equal to the product between the monkey's mass and its acceleration, so we can find the acceleration:

F-F_f=ma\\a=\frac{F-F_f}{m}=\frac{345 N-48.6 N}{31.0 kg}=9.6 m/s^2

5) 462.3 N

The horizontal component of the pushing force is:

F_x = F cos \theta = (648 N)(cos 25^{\circ})=587.3 N

The frictional force, acting in the opposite direction, is

F_f = \mu mg=(0.17)(75.0 kg)(9.8 m/s^2)=125.0 N

where \mu is the coefficient of friction and m is the mass of the box.

The net force on the box is therefore given by the net force on the horizontal direction:

F_{net}=F_x -F_f=587.3 N -125.0 N=462.3 N

6) 89.5 N

First of all we need to calculate the total weight of the table and the items above it.

The weight of the table is:

W=mg=(25.0 kg)(9.8 m/s^2)=245 N

So the total weight of the table and the items is

W=245 N+63 N+12 N+44 N+24 N+9N+10N=407 N

The force needed to get the table moving must be at least equal to the frictional force, which is equal to the product between the coefficient of friction and the weight of the all stuff:

F=F_f = \mu W=(0.22)(407 N)=89.5 N

7 0
3 years ago
What color dose red cabbage juice turn when it is mixed with lemon juice
miss Akunina [59]
I think it’s green but idk
7 0
4 years ago
Ocean waves are hitting a beach with a frequency of 0.100 Hz. Their average wavelength is 15.0 m. What is their average speed?
den301095 [7]

Answer:

Average speed=1.5 m/s

Frequency of pendulum=93.75Hz

Explanation:

We are given

Frequency, f=0.100Hz

Average wavelength =\lambda=15m

Speed of pendulum, v=30m/s

Wavelength, \lambda'=0.32m

We have to find the average speed and frequency of pendulum.

We know that

Speed,v=\lambda f

Using the formula

Average speed,v=15\times 0.1=1.5m/s

Hence, the average speed =1.5m/s

Frequency, f=\frac{v}{\lambda'}

Using the formula

f=\frac{30}{0.32}

f=93.75Hz

Hence, the frequency of a pendulum=93.75Hz

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3 years ago
Find the electric force acting on an alpha particle in a horizontal electric field of 600N/C
Sergeeva-Olga [200]
Since an alpha particle has 2 protons and no negative particles (electrons) to balance the net charge, its charge is
Q=2(1.6e-19)=3.2e-19C.
The force on a charged particle is F=QE so
(3.2e-19C)(600N/C)=1.92e-16N
6 0
3 years ago
Electrons do not move unless they are attracted to an electromagnet <br><br> True or false
Tpy6a [65]

The answer is false , because they move without an electromagnetic

3 0
3 years ago
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