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vovikov84 [41]
3 years ago
6

I need Someone to help me with this problems equation and answer must be correct (100 Points)

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
3 0

Answer:

1) 3x+18=45       x=9

2)8-5x=-7          x=3

3)3+2x=15         x=6

4) 12million - 2 million  = 10 million

Step-by-step explanation:

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Find a general solution of y" + 4y = 0.
klio [65]

Answer:

y(x)=C_{1}cos2x+C_{2}sin(2x)

Step-by-step explanation:

It is a linear homogeneous differential equation with constant coefficients:

y" + 4y = 0

Its characteristic equation:

r^2+4=0

r1=2i

r2=-2i

We use these roots in order to find the general solution:

y(x)=C_{1}cos2x+C_{2}sin(2x)

8 0
3 years ago
Which of the following is most likely the next step in the series?<br> I need help pls :’(
LUCKY_DIMON [66]

Answer:

The answer is: A

Step-by-step explanation:

The way the numbers are counting around the wheel and the color pattern all match A

6 0
3 years ago
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What are two features of any density curve
Aleksandr [31]
1. the total of an area under the curve must be equal to one. 2. Every point of the curve must have an vertical height that is 0 or greater.
3 0
3 years ago
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The steps for solving the equation 2x - 3 = 7 are listed below:
goblinko [34]
You are inversing for subtraction which is addition so D
3 0
4 years ago
2x^2+3x-2, a=0 How do I find the derivative?
Ghella [55]

You can use the definition:

\displaystyle f'(x) = \lim_{h\to0}\frac{f(x+h)-f(x)}h

Then if

f(x) = 2x^2+3x-2

we have

f(x+h) = 2(x+h)^2+3(x+h) - 2 = 2x^2 + 4xh+2h^2+3x+3h-2

Then the derivative is

\displaystyle f'(x) = \lim_{h\to0}\frac{(2x^2+4xh+2h^2+3x+3h-2)-(2x^2+3x-2)}h \\\\ f'(x) = \lim_{h\to0}\frac{4xh+2h^2+3h}h \\\\ f'(x) = \lim_{h\to0}(4x+2h+3) = \boxed{4x+3}

I'm guessing the second part of the question asks you to find the tangent line to <em>f(x)</em> at the point <em>a</em> = 0. The slope of the tangent line to this point is

f'(0) = 4(0) + 3 = 3

and when <em>a</em> = 0, we have <em>f(a)</em> = <em>f</em> (0) = -2, so the graph of <em>f(x)</em> passes through the point (0, -2).

Use the point-slope formula to get the equation of the tangent line:

<em>y</em> - (-2) = 3 (<em>x</em> - 0)

<em>y</em> + 2 = 3<em>x</em>

<em>y</em> = 3<em>x</em> - 2

5 0
3 years ago
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